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Grace [21]
2 years ago
13

ALGEBRA Jake Duffy drove 12,568 miles

Mathematics
1 answer:
kirza4 [7]2 years ago
5 0

Answer:

The cost per mile that Jack Duffy charge $0.278 per miles , i.e option B  

Step-by-step explanation:

Given as :

The distance drove by Jack Duffy = d = 12,568 miles

The fixed costs totaled = $1,485.00

The variable cost totaled = $2,015.75

Let The cost per mile that Jack Duffy charge = $x cost per miles

Now, According to question

The totaled cost = The fixed costs + The variable cost

Or, The totaled cost = $1,485.00 + $2,015.75

I.e  The totaled cost = $3500.75

Now,

The cost per mile that Jack Duffy charge = \dfrac{\extrm Total cost}{\textrm Total Distance}

I.e x = \dfrac{3500.75}{12568}

∴ x = $0.278 per miles

So,The cost per mile that Jack Duffy charge = x = $0.278 per miles .

Hence,The cost per mile that Jack Duffy charge $0.278 per miles , i.e option B  Answer

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solniwko [45]

Answer:

Step-by-step explanation:

Hello, please consider the following.

A. (x minus y)(y minus x)

  (x-y)(y-x)=-(x-y)(x-y)=-(x-y)^2

   This is not a difference of squares.

B. (6 minus y)(6 minus y)

   (6-y)(6-y)=(6-y)^2

   This is not a difference of squares.

C. (3 + x z)(negative 3 + x z)

   This is a difference of squares.

   \boxed{(3+xz)(-3+xz)=(xz+3)(xz-3)=(xz)^2-3^2}

D. (y squared minus x y)(y squared + x y)

   This is a difference of squares.

   \boxed{(y^2-xy)(y^2+xy)=(y^2)^2-(xy)^2}

E. (64 y squared + x squared)(negative x squared + 64 y squared)

   This is a difference of squares.

   \boxed{(64y^2+x^2)(-x^2+64y^2)=(64y^2+x^2)(64y^2-x^2)=(64y^2)^2-(x^2)^2}

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

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2 years ago
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Problem Lois and Clark own a company that sells wagons. The amount they pay each of their sales employees (in dollars) is given
Oxana [17]
12h + 30w.....where h = hrs worked and w = wagons sold

so if an employee works 6 hrs and sells 3 wagons....then h = 6 and w = 3

12h + 30w
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2 years ago
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Black_prince [1.1K]

Answer: Real world problem is "A student have c toffee he distribute \frac{3}{4}th part of those toffees to his friends. He gave total 21 toffees to his friend".

Explanation:

Let a student have c number of toffees in his bag.

It is given that he distribute \frac{3}{4}th part of those toffees to his friends.

The \frac{3}{4}th part of c toffees is,

\frac{3c}{4}

The total number of distributed toffees is 21.

\frac{3c}{4}=21

It is the same as given equation.

If we change the equation in words it means the \frac{3}{4}th part of a number c is 21.

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2 years ago
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Answer:

<h2>{5}</h2>

Step-by-step explanation:

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Answer:

Joint variation says that:

if x \propto y and x \propto z

then the equation is in the form of:

x = kyz, where, k is the constant of variation.

As per the statement:

If x varies jointly as y and z

then by definition we have;

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Solve for k;  

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then

Substitute these in [1] we have;

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Divide both sides by 36 we have;

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Simplify:

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Substitute these value we have;

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Divide both sides by 12 we have;

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