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raketka [301]
2 years ago
14

A geometry teacher asked Radric to define "parallel lines." Radric said that parallel lines are lines in a plane that do not hav

e any points in common. Is Radric's definition valid?
Mathematics
2 answers:
Dvinal [7]2 years ago
7 0

Answer:

Radric answer is Right.

Step-by-step explanation:

  • Radric said that the parallel lines are the lines in a plane that do not have any points in common.
  • He is right as he is talking about the lines in a plane i.e the line are not intersecting each other even till infinity .
  • It is not possible for two non-parallel lines not intersect each other in a plane at any point. Even, if there is a small deviation in the two lines they will intersect at some point in the plane.

So the Radric is right and his answer is valid.  

UkoKoshka [18]2 years ago
6 0

Answer: The answer is Yes.

Step-by-step explanation:  Given in the question that Radric was asked to define "parallel lines" and he said that parallel lines are lines in a plane that do not have any points in common. We are to decide whether Radric's definition is valid or not.

Parallel lines are defined as lines in a plane which never meets or any two lines in a plane which do not intersect each other at any point are called parallel.

Thus, Radric's definition is valid.

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Mr. Peterson needs topsoil for his garden. His rectangular garden is 78 in long and 48 in wide. A bag of topsoil covers an area
nata0808 [166]

Answer:

3744 inches squared, and 8 bags

Step-by-step explanation:

Ⓗⓘ ⓣⓗⓔⓡⓔ

˜”*°•.˜”*°• Area: •°*”˜.•°*”˜

Well, the formula for area is L*W

L=78 inches

W=48 inches

78*48=3744 inches squared

˜”*°•.˜”*°• Number of bags: •°*”˜.•°*”˜

3744/500=7.448

So he would need to buy 8 bags

(っ◔◡◔)っ ♥ Hope this helped! Have a great day! :) ♥

4 0
1 year ago
If the parabola of the form y = a(x – h)2 + k is always shifted horizontally h units and vertically k units, then its vertex is
Marta_Voda [28]
The parabola defined by
y = a(x - h)² + k
has its vertex at (h,k).

After a shift by h units right, followed by a shift of k units vertically, the parabola is defined by
y = a(x - 2h)² + 2k
which has its vertex at (2h, 2k).

Answer: The vertex gets shifted by h units horizontally and k units vertically.
8 0
2 years ago
Read 2 more answers
In the diagram, P1P2 and Q1Q2are the perpendicular bisectors of AB¯¯¯¯¯ and BC¯¯¯¯¯, respectively. A1A2 and B1B2 are the angle b
4vir4ik [10]
We have to choose the correct answer for the center of the circumscribed circle of a triangle. The center of the circumscribed circle of a triangle is where the perpendicular bisectors of a triangle intersects. In this case P1P2 and Q1Q2 are perpendicular bisectors of sides AB and BC, respectively and they intersect at point P. S is the point where the angle bisectors intersect ( it is the center of the inscribed circle ). Answer: <span>P.</span>
7 0
1 year ago
What number should go in the space? Multiplying by 1.98 is the same as increasing by _____%.
sattari [20]
1.98
1.98*100
198

Multiplying by 1.98 is the same as increasing by 198%.
4 0
1 year ago
Suppose that birth weights are normally distributed with a mean of 3466 grams and a standard deviation of 546 grams. Babies weig
Anon25 [30]

Answer:

3.84% probability that it has a low birth weight

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 3466, \sigma = 546

If we randomly select a baby, what is the probability that it has a low birth weight?

This is the pvalue of Z when X = 2500. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{2500 - 3466}{546}

Z = -1.77

Z = -1.77 has a pvalue of 0.0384

3.84% probability that it has a low birth weight

3 0
2 years ago
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