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Annette [7]
2 years ago
13

A 16\dfrac1216 2 1 ? 16, start fraction, 1, divided by, 2, end fraction kilometer stretch of road needs repairs. Workers can rep

air 2\dfrac142 4 1 ? 2, start fraction, 1, divided by, 4, end fraction kilometer of road per week. How many weeks will it take to repair this stretch of road?
Mathematics
2 answers:
hram777 [196]2 years ago
6 0

Answer:

7\frac{1}{3}\text{ weeks}

Step-by-step explanation:

Given,

Total distance have to stretch = 16\frac{1}{2} km,

Also, the distance repaired by workers each week = 2\frac{1}{4} km,

Thus, the number of weeks required to repair whole distance

=\frac{\text{Total distance have to stretch}}{\text{Distance repaired in one week}}

=\frac{16\frac{1}{2}}{2\frac{1}{4}}

=\frac{\frac{33}{2}}{\frac{9}{4}}

=\frac{66}{9}

=7\frac{1}{3}

alexdok [17]2 years ago
5 0

Answer: It will take 7\dfrac{1}{3} weeks to repair this stretch of road.

Step-by-step explanation:

Since we have given that

Part of road needs repair = 16\dfrac{1}{2}=\dfrac{33}{2}

Part of road worker can repair per week = 2\dfrac{1}{4}=\dfrac{9}{4}

We need to find the number of weeks that it will take to repair this stretch of road.

So, Number of weeks is given by

\dfrac{33}{2}\div \dfrac{9}{4}\\\\=\dfrac{33}{2}\times \dfrac{4}{9}\\\\=\dfrac{66}{9}\\\\=\dfrac{22}{3}\\\\=7\dfrac{1}{3}

Hence, it will take 7\dfrac{1}{3} weeks to repair this stretch of road.

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Step-by-step explanation:

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4

Step-by-step explanation:

Let's set up an equation using the formula for the area of a triangle.

Hint #22 / 3

\begin{aligned} \text{Area of a triangle} &= \dfrac12 \cdot \text{base} \cdot \text{height}\\\\ 12&= \dfrac12 \cdot 6 \cdot x \\\\ 12&= 3x \\\\ \dfrac{12}{\blueD{3}}&= \dfrac{3x}{\blueD{3}} ~~~~~~~\text{divide both sides by } {\blueD{ 3}}\\\\ \dfrac{12}{\blueD{3}}&= \dfrac{\cancel{3}x}{\blueD{\cancel{3}}}\\\\ x &=\dfrac{12}{\blueD{3}}\\\\ x &=4\end{aligned}  

Area of a triangle

12

12

3

12

​  

 

3

12

​  

 

x

x

​  

 

=  

2

1

​  

⋅base⋅height

=  

2

1

​  

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=3x

=  

3

3x

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=  

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