Answer:
Step-by-step explanation:
Since we are not told what to find, we can as well find the time taken by the rocket to reach its maximum height as shown
The rocket reaches its maximum height when the velocity is zero
v = dh/dt
v = -32t+64
Since v = 0 at maximum height
0 = -32t+64
32t = 64
t = 64/32
t = 2secs
Hence the rocket reaches the maximum height after 2secs
You can start with the equation of
(1/6)x8+(1/8)x6+(1/12)x X=3
Multiply by common denominator of 24 to get
32+18+2x=72
Simplify it we get
50+2x=72
Eliminate using algebra (because it’s add 50 take away the 50 on both sides)
2x=22
Because it’s X2 divide by 2 on both sides
x=11
It will take 11 days
Answer:
The value of q that maximize the profit is q=200 units
Step-by-step explanation:
we know that
The profit is equal to the revenue minus the cost
we have
---> the revenue
---> the cost
The profit P(q) is equal to

substitute the given values



This is a vertical parabola open downward (because the leading coefficient is negative)
The vertex represent a maximum
The x-coordinate of the vertex represent the value of q that maximize the profit
The y-coordinate of the vertex represent the maximum profit
using a graphing tool
Graph the quadratic equation
The vertex is the point (200,-120)
see the attached figure
therefore
The value of q that maximize the profit is q=200 units
Answer:

Step-by-step explanation:

Group similar terms together:

Add the term
:

Subtract the term a:
