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Ugo [173]
2 years ago
7

The instructor had saved $3,500 and rents an apartment for $275 monthly. He believes the point (6, 1850) would be on the equatio

n of the line. Is he correct? Explain how to check if a point is on a line
Mathematics
2 answers:
elena-s [515]2 years ago
6 0

Sample Answer: Write the equation using slope and y-intercept in slope-intercept form, y = –275x + 3500. Then, substitute the x and y values of the point into the equation, 1850 = –275(6) + 3500. Simplify to see if both sides are equivalent. Yes, the instructor is correct because both sides are equivalent.



mafiozo [28]2 years ago
6 0
Y = -275x + 3500
(6,1850)....x = 6 and y = 1850
now we sub
1850 = -275(6) + 3500
1850 = - 1650 + 3500
1850 = 1850 (correct)

so yes, (6,1850) is a point on the line
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. A rocket carrying fireworks is launched from a hill above a lake. The rocket will fall into lake after exploding at its maximu
RoseWind [281]

Answer:

Step-by-step explanation:

Since we are not told what to find, we can as well find the time taken by the rocket to reach its maximum height as shown

The rocket reaches its maximum height when the velocity is zero

v = dh/dt

v = -32t+64

Since v = 0 at maximum height

0 = -32t+64

32t = 64

t = 64/32

t = 2secs

Hence the rocket reaches the maximum height after 2secs

8 0
2 years ago
A company contracts to paint 3 houses. Mr. Brown can paint a house in 6 days while Black would take 8 days and Blue 12 days. Aft
AleksAgata [21]
You can start with the equation of
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6 0
2 years ago
Find the quantity q that maximizes profit if the total revenue, R(q), and total cost, C(q) are given in dollars by R(q)=3q−0.002
marysya [2.9K]

Answer:

The value of q that maximize the profit is q=200 units

Step-by-step explanation:

we know that

The profit is equal to the revenue minus the cost

we have

R(q)=3q-0.002q^{2} ---> the revenue

C(q)=200+2.2q ---> the cost

The profit  P(q) is equal to

P(q)=R(q)-C(q)

substitute the given values

P(q)=(3q-0.002q^{2})-(200+2.2q)

P(q)=3q-0.002q^{2}-200-2.2q

P(q)=-0.002q^{2}+0.8q-200

This is a vertical parabola open downward (because the leading coefficient is negative)

The vertex represent a maximum

The x-coordinate of the vertex represent the value of q that maximize the profit

The y-coordinate of the vertex represent the maximum profit

using a graphing tool

Graph the quadratic equation

The vertex is the point (200,-120)

see the attached figure

therefore

The value of q that maximize the profit is q=200 units

6 0
2 years ago
Can someone help me on question 14. Please show steps
zavuch27 [327]

Answer:

0.5a+7.5b^2

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4b^2+3.5a-2a+3.5b^2-a

Group similar terms together:

3.5a-2a-a+4b^2+3.5b^2

Add the term b^2:

3.5a-2a-a+7.5b^2

Subtract the term a:

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Lisa wrote the following statement: "You can only draw one unique isosceles triangle that contains an angle of 65°." Which state
JulijaS [17]
Triangles always equal 180 degrees

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