Answer:
In kJ/kg.K - 1.005 kJ/kg degrees Kalvin.
In J/g.°C - 1.005 J/g °C
In kcal/ kg °C 0.240 kcal/kg °C
In Btu/lbm-°F 0.240 Btu/lbm degree F
Step-by-step explanation:
given data:
specific heat of air = 1.005 kJ/kg °C
In kJ/kg.K
1.005 kJ./kg °C = 1.005 kJ/kg degrees Kelvin.
In J/g.°C
In kcal/ kg °C
For kJ/kg. °C to Btu/lbm-°F
Need to convert by taking following conversion ,From kJ to Btu, from kg to lbm and from degrees C to F.
1.005 kJ/kg C = 0.240 Btu/lbm degree F
Answer:
0.659 is the probability that a tutor charges between $10 and $20 per hour.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = $15 per hour
Standard Deviation, σ = $5.25 per hour
We are given that the distribution of tutoring prices is a bell shaped distribution that is a normal distribution.
Formula:
P( tutor charges between $10 and $20 per hour)
0.659 is the probability that a tutor charges between $10 and $20 per hour.