S = d/t
st = d
t = d/s
The time going is t1.
The time returning is t2.
The total time is 4 hours, so we have t1 + t2 = 4
The speed of the current is c.
The speed going is 9 + c.
The speed returning is 9 - c.
t1 = 16/(9 + c)
t2 = 16/(9 - c)
t1 + t2 = 16/(9 + c) + 16/(9 - c)
4 = 16/(9 - c) + 16/(9 + c)
1 = 4/(9 - c) + 4/(9 + c)
(9 + c)(9 - c) = 4(9 - c) + 4(9 + c)
81 - c^2 = 36 - 4c + 36 + 4c
81 - c^2 = 72
c^2 = 9
c^2 - 9 = 0
(c + 3)(c - 3) = 0
c + 3 = 0 or c - 3 = 0
c = -3 or c = 3
We discard the negative answer, and we get c = 3.
The speed of the current is 3 mph.
Answer
14/15 kg
Step-by-step explanation:
Rewriting our equation with parts separated
=1+215−15
Solving the fraction parts
2/15−15=?
Find the LCD of 2/15 and 1/5 and rewrite to solve with the equivalent fractions.
LCD = 15
2/15−3/15=−1/15
Combining the whole and fraction parts
1−1/15=14/15
Solution by Formulas
converting mixed numbers to fractions, our initial equation becomes,
17/15−15
Applying the fractions formula for subtraction,
=(17×5)−(1×15)15×5
=85−15/75
=70/75
Simplifying 70/75, the answer is
=14/15
Answer:
A) f(-3) = g(-4)
Step-by-step explanation: hope it helps
HELLO,
Your answer is 130-50=80
You would have to make 80 dollars,
So 8 dollars per hour (of course that is below minimum wage that means you need a raise).
Therefore, you need to mow lawns for 10 hours
Thanks for posting your question here on brainly.
Hope this helps you.
Let me know if its correct.
LIST has 5 lines: L has two, I has 1, T as 2. It has one curve: S.
Therefore LIST = 51
LOAD has 6 lines, 2 curves.
L has 2 lines, A has 3 lines, D has one line (also one curve)
O is one curve, D has one, so LOAD= 62
