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2 years ago

A sample of 150 CBC students was taken, and each student filled out a

Mathematics

1 answer:

Ludmilka [50]2 years ago

3 0

Answer:

The probability of the event BC

= the probability of B * C = 48.6667% * 70%

= 34.0667%

Step-by-step explanation:

Probability of A, students with children = 44/150 = 29.3333%

Probability of B, students enrolled in at least 12 credits = 73/150 = 48.6667%

Probability of C, students working at least 10 hours per week = 105/150 = 70%

Therefore, the Probability of BC, students enrolled in 12 credits and working 10 hours per week

= 48.6667% * 70%

= 34.0667%

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Ahmed is riding the elevator in a building. The building has floors above and below ground level. Ahmed uses the expression belo

cluponka [151]

Answer:

He moved 6 floors up, then moved 8 floors down. So he is now 2 floors below ground level.

I hope this helps.

Step-by-step explanation:

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2 years ago

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The graph of the parent function f(x) = x2 is dashed and the graph of the transformed function g(x) = (x – h)2 is solid. Use the

STALIN [3.7K]

The graph of the parent function f(x) = x2 is dashed and the graph of the transformed function g(x) = (x – h)2 is solid.

If h=3 the vertex shifts to (3,0).

If h=-5 the vertex is shifted to (-5,0)

I hope this helps! Sorry no one got back to you in the past few days ):

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1 year ago

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Please solve this equation

Darya [45]

Answer: if you simplify the equation, your answer should be 16

Step-by-step explanation: Simplify 2+22+22+2 to 444.

8÷2×48\div 2\times 48÷2×4

Simplify 8÷28\div 28÷2 to 444.

4×44\times 44×4

Simplify.

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2 years ago

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Approximately how much principal would need to be placed into an account earning 3.575% interest compounded quarterly so that it

Ainat [17]

Answer-

$23377 must be deposited to get $68000 at the end of 30 years.

Solution-

We know that for compound interest,

$A=P(1+\dfrac{r}{n})^{nt}$

Where,

A = Future amount = $68,000

P = ??

r = 3.575% annual = 0.03575

n = 4 as interest is compounded quarterly

t = time in year = 30 years

Putting the values,

$\Rightarrow 68000=P(1+\dfrac{0.03575}{4})^{4\times 30}$

$\Rightarrow 68000=P(1.0089375)^{120}$

$\Rightarrow P=\dfrac{68000}{(1.0089375)^{120}}$

$\Rightarrow P=23377.45$

Therefore, $23377 must be deposited to get $68000 at the end of 30 years.

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1 year ago

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iren [92.7K]

For the last part, you have to find where $f'(t)$ attains its maximum over $0\le t\le8$ . We have

$f'(t)=-6\sin3t+6\cos2t$

so that

$f''(t)=-18\cos3t-12\sin2t$

with critical points at $t$ such that

$-18\cos3t-12\sin2t=0$

$3\cos3t+2\sin2t=0$

$3(\cos^3t-3\cos t\sin^2t)+4\sin t\cos t=0$

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$\cos t(12\sin^2t-4\sin t-3)=0$

So either

$\cos t=0\implies t=\dfrac{(2n+1)\pi}2$

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