All categories

2 years ago

A sample of 150 CBC students was taken, and each student filled out a

Mathematics

1 answer:

Ludmilka [50]2 years ago

3 0

Answer:

The probability of the event BC

= the probability of B * C = 48.6667% * 70%

= 34.0667%

Step-by-step explanation:

Probability of A, students with children = 44/150 = 29.3333%

Probability of B, students enrolled in at least 12 credits = 73/150 = 48.6667%

Probability of C, students working at least 10 hours per week = 105/150 = 70%

Therefore, the Probability of BC, students enrolled in 12 credits and working 10 hours per week

= 48.6667% * 70%

= 34.0667%

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anonymous 4 years ago You have a graduated cylinder that you use to measure volume. The cylinder is marked in 0.1 ml increments.

Snezhnost [94]

B 1.0 ml a and c give a more precise measurement going to the hundredths and thousandths place

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2 years ago

A frequency distribution is a tabular summary of data showing the a. number of items in several classes. b. relative percentage

Viefleur [7K]

Answer:

The answer is a: Number of items in several classes.

Step-by-step explanation:

Frequency distributions are tables that represent the number of times a specific data, number object etc appears in a sample. So for example if we have this data

2,2,4,4,6,6,6,8,8,10

The frequency distributions is

Number frequency

2 2

4 2

6 3

8 2

10 1

The other options are identical (c and are the same as percentages can be expressed as fractions. Relative percentages or fractions are tables that express the weight that each category has in the entire data. An example for our data would be: (10 are the total number of obs)

Number Fraction/%

2 2/10 or 20%

4 2/10 or 20%

6 3/10 or 30%

8 2/10 or 20%

10 1/10 or 10%

6 0

2 years ago

Paula and Kawai shared $312 in the ratio of 6:7. How much money did each person get?

Maslowich

Answer:

Paula get $\$144$ and Kawai get $\$168$ .

Step-by-step explanation:

Given: Paula and Kawai shared $\$312$ in the ratio of $6:7$ .

To find: How much money did each person get?

Solution:

We have,

Paula and Kawai shared $\$312$ in the ratio of $6:7$ .

So, let Paula get $\$6x$ and Kawai get $\$7x$ .

As per the question,

$6x+7x=312$

$\implies13x=312$

$\implies x=\frac{312}{13} =24$

Therefore, Paula get $6\times 24=\$144$ , and Kawai get $7\times 24=\$168$ .

Hence, Paula get $\$144$ and Kawai get $\$168$ .

6 0

2 years ago

Given a rectangular pyramid and a rectangular prism that have the same base and same height, how do their volumes compare? If th

Luden [163]

We know that
volume of a rectangular prism =B*h------> equation 1
where
B is the area of the base
h is the height

volume of a rectangular pyramid=(1/3)*B*h-----> equation 2
where
B is the area of the base
h is the height

substitute equation 1 in equation 2
volume of a rectangular pyramid=(1/3)*volume of a rectangular prism

the answer part a) is
volume of a rectangular pyramid=(1/3)*volume of a rectangular prism

Part b) If the pyramid was full of water, how much of the prism would it fill up?

the answer part b) is
If the pyramid was filled with water, the prism would only fill 1/3 of its volume

Part c) Name another pair of three-dimensional objects that have a relationship similar to this

cones and cylinders

volume of a cylinder =B*h------> equation 1
where
B is the area of the base
h is the height 

volume of a cone=(1/3)*B*h-----> equation 2
where
B is the area of the base
h is the height

substitute equation 1 in equation 2
volume of a cone=(1/3)*volume of a cylinder

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2 years ago

The coordinate values of the vertices of △klm are integers. triangle klm has vertices located at (1, 1), (5, 4) and (5, 1). whic

worty [1.4K]

The rest of the queastion is :
 A) (-1, 1), (-1, 4), (2, 1)
B) (0, 0), (3, 4), (0, 5)
C) (-1, 1), (-4, 5), (-1, 5)
D) (0, 0), (-5, 0), (0, 4)
==============================

The distance between two points (x₁,y₁),(x₂,y₂) = d
$d = \sqrt{ (x2-x1)^{2} + (y2-y1)^{2} }$

we have K(1, 1), L(5, 4) and M(5, 1)
we will find the length between each two points.
KL = $d = \sqrt{ (5-1)^{2} + (4-1)^{2} }$ = 5
LM = $d = \sqrt{ (5-5)^{2} + (1-4)^{2} }$ = 3
KM = $d = \sqrt{ (5-1)^{2} + (1-1)^{2} }$ = 4

now check each group from the choices
the group that will give the same result will be the correct choice.
The correct choice is C
C) (-1, 1), (-4, 5), (-1, 5)

check the answer;
K'(-1, 1), L'(-4, 5), M'(-1, 5)

K'L' = $d = \sqrt{ (-4+1)^{2} + (5-1)^{2} }$ = 5
L'M' = $d = \sqrt{ (-1+4)^{2} + (5-5)^{2} }$ = 3
K'M' = $d = \sqrt{ (-1+1)^{2} + (5-1)^{2} }$ = 4

6 0

2 years ago