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2 years ago

Jorge is making 6 large salads and 4 small salads how many cherry tomatoes does he need?

Mathematics

2 answers:

damaskus [11]2 years ago

8 0

Answer:10

Step-by-step explanation:

kati45 [8]2 years ago

6 0

The answer will be 74 cherry tomatoes

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Please answer this I really need help, Ariel spent a total of $3.42 buying dried apricots from the bulk bins, which were on sale

Kamila [148]

Answer:

1.2 lbs

Step-by-step explanation:

This problem is set up so that the total price is proportional to the price per pound, so to find the proportion you would divide the total cost by the cost per pound. 3.42/2.85 = 1.2, so the answer is 1.2 pounds.

5 0

2 years ago

Dan pays £220 per week in rent. His landlord decides to increase the rent by 2.5%. How much rent does he pay now?

Dima020 [189]

Answer:

225.5

Step-by-step explanation:

So, you would start by doing

220 times 2.5% that would equal 5.5

Then you would add

220 + 5.5 = 225.5

Therefore your answer will be 225.5

8 0

2 years ago

Read 2 more answers

Ramon wants to plant cucumbers and tomatoes in his garden. He has room for

yarga [219]

Answer:

Number of Cucumbers = 12

Number of Tomatoes = 4

Step-by-step explanation:

Let number of cucumber be c and number of tomatoes be t

Since he has room for 16 plants, we can write:

c + t = 16

He wants to plant 3 times as many cucumbers as tomatoes. We can write:

c = 3t

We can substitute this in 1st equation and solve for t:

c + t = 16

3t + t = 16

4t = 16

t = 16/4 = 4

And c = 3t

c = 3(4) = 12

Number of Cucumbers = 12

Number of Tomatoes = 4

6 0

2 years ago

Read 2 more answers

g An irate student complained that the cost of textbooks was too high. He randomly surveyed 36 other students and found that the

blagie [28]

Answer:

A 90% confidence interval of the true mean is [$119.86, $123.34].

Step-by-step explanation:

We are given that an irate student complained that the cost of textbooks was too high. He randomly surveyed 36 other students and found that the mean amount of money spent on textbooks was $121.60.

Also, the standard deviation of the population was $6.36.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean amount of money spent on textbooks = $121.60

$\sigma$ = population standard deviation = $6.36

n = sample of students = 36

$\mu$ = population mean

Here for constructing a 90% confidence interval we have used One-sample z-test statistics as we know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-1.645 < N(0,1) < 1.645) = 0.90 {As the critical value of z at 5% level

of significance are -1.645 & 1.645}

P(-1.645 < $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ < 1.645) = 0.90

P( $-1.645 \times {\frac{\sigma}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.645 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.90

P( $\bar X-1.645 \times {\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.645 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.90

90% confidence interval for $\mu$ = [ $\bar X-1.645 \times {\frac{\sigma}{\sqrt{n} } }$ , $\bar X+1.645 \times {\frac{\sigma}{\sqrt{n} } }$ ]

= [ $121.60-1.645 \times {\frac{6.36}{\sqrt{36} } }$ , $121.60+1.645 \times {\frac{6.36}{\sqrt{36} } }$ ]

= [$119.86, $123.34]

Therefore, a 90% confidence interval of the true mean is [$119.86, $123.34].

5 0

2 years ago

An appliance manufacturer recommends keeping the freezer set at -18 degrees C. Explain what the absolute value tells us about -1

LenaWriter [7]

Answer: I do not know honestly

7 0

2 years ago