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2 years ago

All angles in the diagram are measured to the nearest degree.

Mathematics

1 answer:

DochEvi [55]2 years ago

6 0

Answer:

lower bound is 110.503 and upper bound is 112.500

Step-by-step explanation:

Given 3 angles around a point we are to find the fourth angle.

The three angles are 59. 108 and 81.

They are rounded off to the nearest degrees.

As per this given, fourth angle = 360-(59+108+81) = 112 degrees

Since angles were rounded off, the extreme chances are

58.5, 107.5, and 80.5 rounded off to 59, 108, and 81 from left side.

Right side maximum is 59.499, 108.499, 81.499 (taken upto 3 decimals) rounded to 59, 108, 81

In the first case, fourth angle would be 112.50 and in the second case, the fourth angle would be 110.503 degrees

Thus lower bound is 110.503 and upper bound is 112.500

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Answer:

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Step-by-step explanation:

Let the amount of money invested by Lian be $x

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1 year ago

This year, a hardware store has a profit of -$6.0 million. This profit is 3/4 of last year's profit. What is last year's profit?

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2 years ago

Two cross sections of a right hexagonal pyramid are obtained by cutting the pyramid with planes parallel to the hexagonal base.

Tanya [424]

Answer:

The larger cross section is 24 meters away from the apex.

Step-by-step explanation:

The cross section of a right hexagonal pyramid is a hexagon; therefore, let us first get some things clear about a hexagon.

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$A=\frac{3\sqrt{3} }{2} r^2$

Where $r$ is the radius of the inscribing circle (or the length of side of the hexagon).

Now we are given the areas of the two cross sections of the right hexagonal pyramid: $A_1=216\:ft^2\: \:\:\:A_2=486\:ft^2$

From these areas we find the radius of the hexagons:

$r_1=\sqrt{\frac{2A_1}{3\sqrt{3} } } =\sqrt{\frac{2*216}{3\sqrt{3} } }=\boxed{9.12ft}$

$r_2=\sqrt{\frac{2A_2}{3\sqrt{3} } } =\sqrt{\frac{2*486}{3\sqrt{3} } }=\boxed{13.68ft}$

Now when we look at the right hexagonal pyramid from the sides ( as shown in the figure attached ), we see that $r_1$ $r_2$ form similar triangles with length $H$

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$\frac{H-8}{r_1} =\frac{H}{r_2}$

We put in the numerical values of $r_1$ , $r_2$ and solve for $H$ :

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Answer:

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