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mrs_skeptik [129]
2 years ago
13

Which is the best approximation for the solution of the system of equations? y = A system of equations. y equals negative StartF

raction 2 over 5 EndFraction x plus 1. y equals 3 x minus 2.x + 1 y = 3x – 2 A coordinate grid with 2 lines. The first line passes through (0, 1) and (5, negative 2). The second line passes through (0, negative 2) and (1, 1). the lines appear the intersect at a point that is almost to 1 and almost to 1. (0.45, 0.88) (0.88, 0.65) (0.88, 1.1) (1.3, 0.88)
Mathematics
2 answers:
vredina [299]2 years ago
8 0

Answer:

(0.88, 0.65)

Step-by-step explanation:

i just took the test

Alla [95]2 years ago
7 0

Answer:

(0.88, 0.65)

Step-by-step explanation:

Given that the two equations of the line are:

y =( -2/5)x + 1 and  y = 3x – 2. To find the solution, we have to solve the equations simultaneously.

y =( -2/5)x + 1       .             .            .      1)

y = 3x – 2             .            .             .      2)

Subtracting equation 1 from equation 2:

3.4x -3 = 0

3.4x = 3

Dividing through by 3.4

3.4x/3.4 = 3/3.4

x = 0.88

To find y, substitute x = 0.88 in equation 2:

y = 3(0.88) - 2

y = 2.65 - 2

y = 0.65

This means that the solution to the system of equations is the point of intersection of the two lines which is at (0.88, 0.65)

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If you are constructing a 95% confidence interval for a normally distributed population when your sample size is 10, what value
Nuetrik [128]

This is something you'll need a T table for, or a calculator that can compute critical T values. Either way, we have n = 10 as our sample size, so df = n-1 = 10-1 = 9 is the degrees of freedom.

If you use a table, look at the row that starts with df = 9. Then look at the column that is labeled "95% confidence"

I show an example below of what I mean.

In that diagram, the row and column mentioned intersect at 2.262 (which is approximate). This value then rounds to 2.26

<h3>Answer:  2.26</h3>

3 0
1 year ago
Jenna dances for 3 hours on sunday, 2 hours on Monday and Tuesday, 1 hour on THursday,1.5 hours oon friday, and 2 hours on Satur
Delicious77 [7]

Answer: The average number of hours she danced per day is 1.9 hours (rounded to the nearest tenth)

Step-by-step explanation: We start by calculating how many hours she danced all together which can be derived as follows;

Summation = 3 +2 +2 + 1 + 1.5 + 2 = 11.5

The number of days she danced which is the observed data is 6 days (she did  not dance at all on Wednesday).

The average (or mean) hours she danced each day can be calculated as

Average = ∑x ÷ x

Where ∑x is the summation of all data and x is number of observed data

Average = (3+2+2+1+1.5+2) ÷ 6

Average = 11.5 ÷ 6

Average = 1.9166

Approximately, average hours danced is 1.9 hours (to the nearest tenth)

8 0
1 year ago
Simplify: StartRoot 64 r Superscript 8 Baseline EndRoot
patriot [66]

Answer:

  8r^4

Step-by-step explanation:

  \sqrt{64r^8} =\sqrt{(8r^4)^2}=\boxed{8r^4}

5 0
2 years ago
Harriet earns the same amount of money each day. Her gross pay at the end of 7 workdays is 35h+56 dollars.which expression repre
statuscvo [17]

The expression 5h+8 represents Harriet's gross pay each day.

Step-by-step explanation:

Given,

Gross pay of Harriet = 35h + 56

This expression represent Harriet's pay for 7 day.

Harriet's gross pay per day = \frac{Gross\ pay}{Number\ of\ days}

Harriet's gross pay per day = \frac{35h+56}{7}

Harriet's gross pay per day = \frac{35h}{7}+\frac{56}{7}

Harriet's gross pay per day = 5h+8

The expression 5h+8 represents Harriet's gross pay each day.

Keywords: division, addition

Learn more about division at:

  • brainly.com/question/106975
  • brainly.com/question/10712420

#LearnwithBrainly

4 0
1 year ago
A set of elementary school student heights are normally distributed with a mean of 105105105 centimeters and a standard deviatio
steposvetlana [31]

Answer:

The proportion of student heights that are between 94.5 and 115.5 is 86.64%

Step-by-step explanation:

We have a mean \mu = 105 and a standard deviation \sigma = 7. For a value x we compute the z-score as (x-\mu)/\sigma, so, for x = 94.5 the z-score is (94.5-105)/7 = -1.5, and for x = 115.5 the z-score is (115.5-105)/7 = 1.5. We are looking for P(-1.5 < z < 1.5) = P(z < 1.5) - P(z < -1.5) = 0.9332 - 0.0668 = 0.8664. Therefore, the proportion of student heights that are between 94.5 and 115.5 is 86.64%

4 0
2 years ago
Read 2 more answers
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