Answer:
Alright well solve for the variable in one of the equation's. then substitute the result of the other equation
Point form: - 175/51, 1/51
Equation form:
x = - 175/51 y = 1/51 Hope this help's :)
Step-by-step explanation:
Let's first write each step of the procedure:
Step 1:
group the x terms together and the terms and together, and move the constant term to the other side of the equation:
x² + 12x + y² + 2y = 1
Step 2:
determine (b ÷ 2) 2 for the x and y terms.
(12 ÷ 2) 2 = 36
and
(2 ÷ 2) 2 = 1
Step 3:
add the values to both sides of the equation.
x2 + 12x + 36 + y2 + 2y + 1 = 1 + 36 + 1
Step 4:
write each trinomial to binomial squared, and simplify the right side.
(x + 6) 2 + (y + 1) 2 = 38
Answer:
the last step is:
(x + 6) 2 + (y + 1) 2 = 38
Answer:
y2 = C1xe^(4x)
Step-by-step explanation:
Given that y1 = e^(4x) is a solution to the differential equation
y'' - 8y' + 16y = 0
We want to find the second solution y2 of the equation using the method of reduction of order.
Let
y2 = uy1
Because y2 is a solution to the differential equation, it satisfies
y2'' - 8y2' + 16y2 = 0
y2 = ue^(4x)
y2' = u'e^(4x) + 4ue^(4x)
y2'' = u''e^(4x) + 4u'e^(4x) + 4u'e^(4x) + 16ue^(4x)
= u''e^(4x) + 8u'e^(4x) + 16ue^(4x)
Using these,
y2'' - 8y2' + 16y2 =
[u''e^(4x) + 8u'e^(4x) + 16ue^(4x)] - 8[u'e^(4x) + 4ue^(4x)] + 16ue^(4x) = 0
u''e^(4x) = 0
Let w = u', then w' = u''
w'e^(4x) = 0
w' = 0
Integrating this, we have
w = C1
But w = u'
u' = C1
Integrating again, we have
u = C1x
But y2 = ue^(4x)
y2 = C1xe^(4x)
And this is the second solution
In this case probability is the likelihood that from 264 customers one customer wins free gallon of milk with his food purchase, or in other words the probability that one customer receives a star on his receipt.
Probability is the ratio of the number of favorable outcomes to the total number of all possible events. From 264 customers, 219 have not received a star. The opposite is to receive a star and that is the situation: (1-219)/264=0.17,
Answer:
c. A two-tailed test should be performed since the alternative hypothesis states that the parameter is not equal to the hypothesized value.
Step-by-step explanation:
Let p1 be the average score on a final exam who texted on a regular basis during the lectures for a particular class
And p2 be the average score on a final exam who did not texted at all during the lectures for a particular class
According to the Cameron's point of interest, null and alternative hypotheses are:
p1 = p2
p1 ≠ p2
Two tailed test should be performed since the alternative hypothesis states that the parameter is not equal to the hypothesized value.