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2 years ago

Don claims that perpendicular lines are lines that intersect such that at least one of the angles is a right angle.

Mathematics

1 answer:

boyakko [2]2 years ago

7 0

A) Intersecting lines allow for the creation for angles with a common vertex

B) if one of the angles is a right angle, the angle the vertical to it must also be a right angle

Step-by-step explanation

C) is not true because linear pairs are supplementary not complementary because a line = 180°

B) it’s true because they are corresponding vertical angles

A) it’s true because they all have the same starting point or vertex

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Telephone computers tv microwave

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2 years ago

Simplify the expression: sin(7x/3)cos(5x/2) - cos(7x/3)sin(5x/2)

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2 years ago

Consider the following formula used to estimate height, h, of a seedling after w weeks since planting:

svp [43]

Answer:

Option B. $w=5h-8$

Step-by-step explanation:

we have

$h=(\frac{1}{5})w+(\frac{8}{5})$

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That means ----> isolate the variable w

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Rewrite

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1 year ago

One option in a roulette game is to bet $2 on red. (There are 18 red compartments, 18 black compartments, and two compartmen

aleksandrvk [35]

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2 years ago

In how many ways can you spell the word ROOM in the grid below? You can start on any letter R, then on each step you can step on

Zina [86]

Answer:

84? Not sure but pretty sure

Step-by-step explanation:

In a straight line, the word can only be spelled on the diagonals, and there are only two diagonals in each direction that have 2 O's.

If 90° and reflex turns are allowed, then the number substantially increases.

Corner R: can only go to the adjacent diagonal O, and from there to one other O, then to any of the 3 M's, for a total of 3 paths.

2nd R from the left: can go to either of two O's, one of which is the same corner O as above. So it has the same 3 paths. The center O can go to any of 4 Os that are adjacent to an M, for a total of 10 more paths. That's 13 paths from the 2nd R.

Middle R can go the three O's on the adjacent row, so can access the three paths available from each corner O along with the 10 paths available from the center O, for a total of 16 paths.

Then paths accessible from the top row of R's are 3 +10 +16 +10 +3 = 42 paths. There are two such rows of R's so a total of 84 paths.

6 0

1 year ago

Read 2 more answers