Which is the graph of linear inequality 6x + 2y > –10? On a coordinate plane, a dashed straight line with negative slope goes
through (negative 2, 0) and (0, negative 6). Everything to the right of the line is shaded. On a coordinate plane, a dashed straight line with negative slope goes through (0, 6) and (2, 0). Everything to the right of the line is shaded. On a coordinate plane, a dashed straight line with positive slope goes through (0, negative 6) and (2, 0). Everything to the right of the line is shaded. On a coordinate plane, a dashed straight line with positive slope goes through (negative 2, 0) and (0, 4). Everything to the right of the line is shaded.
1 answer:
Answer:
On a coordinate plane, a dashed straight line with negative slope goes through (negative -5/3, 0) and (0, negative 5). Everything to the right of the line is shaded
Step-by-step explanation:
6x + 2y > –10
Solve for y
Subtract 6x from each side
2y > -6x -10
Divide by 2
y > -3x - 5
The y intercept is -5 and the slope is -3
The x intercept is -5/3
The line is dashed and shaded to the right
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Answer:
So then P =11000 is the minimum that the least populated district could have.
Step-by-step explanation:
We have a big total of N = 132000 for the population.
And we know that we divide this population into 11 districts
And we have this info given "no district is to have a population that is more than 10 percent greater than the population of any other district"
Let's assume that P represent our minimum value for a district in the population. The range of possible values for the population of each district would be between P and 1.1 P
The interest on this case is find the minimum value for P and in order to do this we can assume that 1 district present the minimum and the other 10 the maximum value 1.1P in order to find which value of P satisfy this condition, and we have this:
So then P =11000 is the minimum that the least populated district could have.