Which is the graph of linear inequality 6x + 2y > –10? On a coordinate plane, a dashed straight line with negative slope goes
through (negative 2, 0) and (0, negative 6). Everything to the right of the line is shaded. On a coordinate plane, a dashed straight line with negative slope goes through (0, 6) and (2, 0). Everything to the right of the line is shaded. On a coordinate plane, a dashed straight line with positive slope goes through (0, negative 6) and (2, 0). Everything to the right of the line is shaded. On a coordinate plane, a dashed straight line with positive slope goes through (negative 2, 0) and (0, 4). Everything to the right of the line is shaded.
1 answer:
Answer:
On a coordinate plane, a dashed straight line with negative slope goes through (negative -5/3, 0) and (0, negative 5). Everything to the right of the line is shaded
Step-by-step explanation:
6x + 2y > –10
Solve for y
Subtract 6x from each side
2y > -6x -10
Divide by 2
y > -3x - 5
The y intercept is -5 and the slope is -3
The x intercept is -5/3
The line is dashed and shaded to the right
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Answer:
See explanation
Step-by-step explanation:
Triangles ΔABC and ΔBAD are congruent. So,
- AB ≅ BA;
- AC ≅ BD;
- BC ≅ AD;
- ∠ABC ≅ ∠BAD;
- ∠BCA ≅ ∠ADB;
- ∠CAB ≅ ∠DBA.
Consider triangles AEC and BED. In these triangles,
- AC ≅ BD;
- ∠EAC ≅ ∠EBD (because ∠CBA ≅ ∠BAD);
- ∠AEC ≅ ∠BED (as vertical angles).
So, ΔAEC ≅ ΔBED. Thus,
AE ≅ EB.
This means that segment CD bisects segment AD.
Answer:
For school A: Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17, IQR=9.5
For school B: Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19, IQR=7.5
No, the box plots are not symmetric.
Step-by-step explanation:
Part A
The given data sets are
School A : 9,14,15,17,17,7,15,6,6
School B : 12,8,13,11,19,15,16,5,8
Arrange the data in ascending order.
School A : 6,6,7,9,14,15,15,17,17
School B : 5,8,8,11,12,13,15,16,19
Divide each data set in four equal parts.
School A : (6,6),(7,9),14,(15,15),(17,17)
School B : (5,8),(8,11),12,(13,15),(16,19)
For school A:
Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17
Interquartile range of the data is
For school B:
Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19
Interquartile range of the data is
Part B:
The box plots are not symmetric because the data values are different. Five number summary and IQR of both the data set are different.