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1 year ago

6 tractors take 10days to collect the harvest. How long would it take 18 tractors to do the same amount of work?

1 answer:

Nutka1998 [239]1 year ago

6 0

This is a question of proportionality. However, it is not direct proportionality as it is expected that as the number of tractors increases, the work is finished faster as opposed to fewer number of tractors. This is referred to as inverse proportionality.

Therefore;
6 tractors ----- 10 days
18 tractors --- x days

Then,
x = (6*10)/18 = 10/3 days = 3 days, and 8 hours.

This means that 18 tractors will take 3 days and 8 hours to collect the same harvest.

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The answer is

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Step-by-step explanation:

we know that

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In this problem we have

$cos(\theta)=\frac{\sqrt{2}}{2}$

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The angle $\theta$ belong to the third or fourth quadrant

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Step 1

Find the value of $sin(\theta)$

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Step 2

Find the value of $tan(\theta)$

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we have

$sin(\theta)=-\frac{\sqrt{2}}{2}$

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