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maxonik [38]
2 years ago
12

Which function represents a vertical stretch of an exponential function? A. f(x)=3(1/2)^x B. f(x)=1/2(3)^x C. f(x)=(3)^2x D. f(x

)=3^(1/2x)
Mathematics
2 answers:
Dimas [21]2 years ago
6 0

Answer:

A. f(x) = 3*(1/2)^x

Step-by-step explanation:

We know that, a function can be stretched or shrinked both horizontally and vertically.

Now, according to our question we are required to look at the vertical stretch of an exponential function.

The general form for a vertical stretch of a function f(x) is k*f(x) where k>1.

So, we compare this form with the options provided.

We see that in option A the exponential function is multiplied by 3 and so the function will be stretched vertically.

Hence, option A is correct.

il63 [147K]2 years ago
5 0
Selection A seems appropriate.

It is of the form k*f(x), where f(x) is an exponential function and k > 1.
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DaniilM [7]
We have the following equation:
 x2 + y2 + 42x + 38y - 47 = 0
 We rewrite the equation:
 x2 + 42x + y2 + 38y - 47 = 0
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 Rewriting we have:
 x2 + 42x + (42/2) ^ 2 + y2 + 38y + (38/2) ^ 2 = 47 + (42/2) ^ 2 + (38/2) ^ 2
 x2 + 42x + 441 + y2 + 38y + 361 = 47 + 441 + 361
 Rewriting we have:
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 The radio is:
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 A circle of the same radius is given by:
 x ^ 2 + y ^ 2 - 50x - 30y + 1 = 0
 Let's check:
 x ^ 2 - 50x + y ^ 2 - 30y + 1 = 0
 x ^ 2 - 50x + y ^ 2 - 30y = - 1
 x ^ 2 - 50x + (-50/2) ^ 2 + y ^ 2 - 30y + (-30/2) ^ 2 = - 1 + (-30/2) ^ 2 + (-50/2) ^ 2
 x ^ 2 - 50x + (-50/2) ^ 2 + y ^ 2 - 30y + (-30/2) ^ 2 = - 1 + 225 + 625
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 Answer:
 
(x + 21) ^ 2 + (y + 19) ^ 2 = 849
 
(x, y) = (-21, -19)
 
r = (849) ^ 2
 
x ^ 2 + y ^ 2 - 50x - 30y + 1 = 0
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2 years ago
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viva [34]

Answer:

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Step-by-step explanation:

As given, AC = BC, its an isosceles triangle.

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Now take triangle ACD,

using Pythagoras theorem,

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AC = 3\sqrt{5}/2

:-)

4 0
2 years ago
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Answer:

477

Step-by-step explanation:

Given that:

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Using the Z probability calculator :

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puteri [66]

Answer:

120 degrees

Step-by-step explanation:

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2 years ago
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