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seropon [69]
2 years ago
5

PLEASE HELP, I’ve been stuck on this question for a whileIn the diagram, AB is divided into equal parts. The coordinates of poin

t A (-3,9), and the coordinates of point B are (9,5).
The coordinates of point C are _____
{Options:
(-1.5,10.5)
(-1.5,8.5)
(-0.5,8.5)
(-0.5,10.5)
The coordinates of point E are _____
{Options:
(1,5,6.5)
(1.5,7.5)
(2.5,6.5)
(2.5,7.5)
The coordinates of point H are _____
{Options:
(5,5.5)
(5,6)
(6,5)
6,6)

Mathematics
2 answers:
pychu [463]2 years ago
7 0

The coordinates of point C are (-1.5, 8.5)

The coordinates of point E are (1.5, 7.5)

The coordinates of point H are (6, 6)

This is for Plato

castortr0y [4]2 years ago
3 0
AB is divided into 8 equal parts and point C is 1 part FROM A TO B, so the ratio is 1:7, with C being 1/7 of the way.  The ratio is k, found by writing the numerator of the ratio (1) over the sum of the numerator and denominator (1+7).  So our k value is 1/8.  Now we need to find the rise and the run (slope) of the points A and B.  m= \frac{5-9}{9-(-3)}.  That gives us a rise of -4 and a run of 12.  The coordinates of C are found in this formula: C(x,y)=[ x_{1} +k(run), y_{1} +k(rise)].  Filling in accordingly, we have C(x,y)=[-3+ \frac{1}{8}(12),9+ \frac{1}{8}(-4)] which simplifies a bit to C(x,y)=(-3+ \frac{3}{2},9- \frac{1}{2}).  Finding common denominators and doing the math gives us that the coordinates of point C are (- \frac{3}{2}, \frac{17}{2}).  There you go!
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Xavier is buying a new pair of snowshoes. They are regularly $85, but they are on sale for $68. What percent is the markdown?
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Step-by-step explanation:

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2 years ago
Performance task: A parade route must start And and at the intersections shown on the map. The city requires that the total dist
GaryK [48]

Answer:

Part A: The proposed route does not meet requirement because it is longer than the maximum required length of 3 miles

Part B: For the total distance is as close to 3 miles as possible, the start point of the parade should be at the point on Broadway with coordinates (9.941, 4.970)

Part C: The coordinates of the cameras stationed half way down each road are;

For central avenue; (4, 2)

For Broadway; (7.97, 2.49)

Step-by-step explanation:

Part A: The length of the given route can be found using the equation for the distance, l, between coordinate points as follows;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

Where for the Broadway potion of the parade route, we have;

(x₁, y₁) = (12, 3)

(x₂, y₂) = (6, 0)

l_1 = \sqrt{\left (0 -3\right )^{2}+\left (6-12 \right )^{2}} = 3 \cdot \sqrt{5}

For the Central Avenue potion of the parade route, we have;

(x₁, y₁) = (6, 0)

(x₂, y₂) = (2, 4)

l_2 = \sqrt{\left (4 -0\right )^{2}+\left (2-6 \right )^{2}} = 4 \cdot \sqrt{2}

Therefore, the total length of the parade route =-3·√5 + 4·√2 = 12.265 unit

The scale of the drawing is 1 unit = 0.25 miles

Therefore;

The actual length of the initial parade =0.25×12.265 unit = 3.09 miles

The proposed route does not meet requirement because it is longer than the maximum required length of 3 miles

Part B:

For an actual length of 3 miles, the length on the scale drawing should be given as follows;

1 unit = 0.25 miles

0.25 miles = 1 unit

1 mile =  1 unit/(0.25) = 4 units

3 miles = 3 × 4 units = 12 units

With the same end point and route, we have;

l_1 = \sqrt{\left (0 -y\right )^{2}+\left (6-x \right )^{2}} = 12 - 4 \cdot \sqrt{2}

y² + (6 - x)² = 176 - 96·√2

y² = 176 - 96·√2 - (6 - x)²............(1)

Also, the gradient of l₁ = (3 - 0)/(12 - 6) = 1/2

Which gives;

y/x = 1/2

y = x/2 ..............................(2)

Equating equation (1) to (2) gives;

176 - 96·√2 - (6 - x)² = (x/2)²

176 - 96·√2 - (6 - x)² - (x/2)²= 0

176 - 96·√2 - (1.25·x²- 12·x+36) = 0

Solving using a graphing calculator, gives;

(x - 9.941)(x + 0.341) = 0

Therefore;

x ≈ 9.941 or x = -0.341

Since l₁ is required to be 12 - 4·√2, we have and positive, we have;

x ≈ 9.941 and y = x/2 ≈ 9.941/2 = 4.97

Therefore, the start point of the parade should be the point (9.941, 4.970) on Broadway so that the total distance is as close to 3 miles as possible

Part C: The coordinates of the cameras stationed half way down each road are;

For central avenue;

Camera location = ((6 + 2)/2, (4 + 0)/2) = (4, 2)

For Broadway;

Camera location = ((6 + 9.941)/2, (0 + 4.970)/2) = (7.97, 2.49).

5 0
2 years ago
Consider the statement: The cube of any rational number is a rational number. a. Write the statement formally using a quantifier
3241004551 [841]

Answer:

(a)∀ r∈ℝ, r∈ℚ, r³∈ℚ

(b)True

Step-by-step explanation:

Definition

1. A real number is said to be rational if and only if there exists two integers a and b such that \frac{a}{b}=r where b≠0.

2. If the product of three numbers is zero, then at least one of the numbers must be zero.

Given Statement

The cube of any rational number is a rational number.

This can be rewritten as:

For all real numbers, if the number is rational then its cube is rational.

If we introduce our variable r,

For all real number r, if r is rational, then r³ is rational.

∀ r∈ℝ, r∈ℚ, r³∈ℚ

(b)The Statement is True.

To prove: The cube of any rational number is rational.

Proof:

We assume that r is a rational number and prove that its cube is a rational number.

By definition, there exists integers a and b such that:

r=\frac{a}{b} where b≠0.

r^3=(\frac{a}{b})^3

r^3=\frac{a^3}{b^3}

Since the cube of an integer is also an integer, a³ and b³ are also integers.

Since b is non-zero, then the zero product property tells us that its cube is also non-zero.

Conclusion:

r^3=\frac{a^3}{b^3} is rational since a³ and b³ are integers and b is non-zero.

6 0
2 years ago
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