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lbvjy [14]
2 years ago
9

Karl is putting a frame around a rectangular photograph. The photograph is 14 inches long and 10 inches wide, and the frame is t

he same width all the way around. What will be the area of the framed photograph?
Mathematics
1 answer:
Sergeu [11.5K]2 years ago
8 0
<h2>The area of the framed photograph = 1156 inch^{2}</h2>

Step-by-step explanation:

Given,

The length of photograph (l) = 14 inches and

The breadth of photograph (b) = 10 inches

To find, the area of the framed photograph = ?

We know that,

The area of the framed photograph = (l + 2b)(l + 2b)

= (14 + 2 × 10) (14 + 2 × 10) inch^{2}

= (14 + 20) (14 + 20) inch^{2}

= (34) (34) inch^{2}

= 1156 inch^{2}

∴ The area of the framed photograph = 1156 inch^{2}

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Brilliant_brown [7]

Answer:

x = 20

x = 140

Step-by-step explanation:

Find the equation for profit P

P = R - C

Substitute the equations for R and C then simplify.

P = 100x − 0.5x² - (20x + 700)

P = -0.5x² + 80x - 700

Find the values of x when profit is $700

P = -0.5x² + 80x - 700

700 = -0.5x² + 80x - 700

0 = -0.5x² + 80x - 1400

This is in the standard form 0 = ax² + bx + c

Use the quadratic formula to find values of x

x = \frac{-b±\sqrt{b^{2}-4ac}  }{2a}

(Ignore Â)

Substitute a b and c.

a = -0.5

b = 80

c = -1400

x = \frac{-(80)±\sqrt{80^{2}-4(-0.5)(-1400)}  }{2(-0.5)}

x = \frac{-80±60}{-1}

Split the formula at the ± so that there are two to get the two x values.

x = \frac{-80+60}{-1}

x = \frac{-80-60}{-1}

x = 20

x = 140

The profit will be $700 when x is 20 or when x is 140.

5 0
2 years ago
Sam is packing gift boxes with fruit. For each apple he packs 3 plums and 5 oranges. If he puts 3 apples in a box, how many plum
Musya8 [376]
You can make an equation.

Let x=oranges
p=plums
n=apples

n= 3p + 5x

So basically we know 1 Apple means Sam will pack 3 plums and 5 oranges

To get 3n which means 3 apples we have to multiply the whole equation by 3


(n= 3p + 5x) x3


3n=9p+15x

So Sam will also put 9 plums and 15 oranges if he puts 3 apples in the box
7 0
2 years ago
Read 2 more answers
The heights of students in a class are normally distributed with mean 55 inches and standard deviation 5 inches. Use the Empiric
maks197457 [2]

Answer:  c)[50,60]

Step-by-step explanation:

The Empirical rule says that , About 68% of the population lies with the one standard deviation from the mean (For normally distribution).

We are given that , The heights of students in a class are normally distributed with mean 55 inches and standard deviation 5 inches.

Then by Empirical rule, about 68% of the heights of students lies between one standard deviation from mean.

i.e. about 68% of the heights of students lies between \text{Mean}\pm\text{Standard deviation}

i.e. about 68% of the heights of students lies between 55\pm5

Here, 55\pm5=(55-5, 55+5)=(50,60)

i.e.  The required interval that contains the middle 68% of the heights. = [50,60]

Hence, the correct answer is c) (50,60)

4 0
2 years ago
PLEASE HELP!! ASAP!!! 20 POINTS. David proved the Law of Cosines with reference to triangle abc using a different method.Arrange
sleet_krkn [62]

Answer:

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Step-by-step explanation:

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Finally, the variations involving other combinations of sides and angles are suggested as being provable in the same way.

3 0
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Katarina [22]

distribute-   8x+4=20

subtract-    8x=20

divide-      20/8=x

answer-   x=2.5


6 0
2 years ago
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