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podryga [215]
2 years ago
9

A standard deck of 52 cards contains four suits: clubs, spades, hearts, and diamonds. Each deck contains an equal number of card

s in each suit. Rochelle chooses a card from the deck, records the suit, and replaces the card. Her results are shown in the table.
Cards
Suit
Observed Frequency
Clubs
29
Spades
13
Hearts
15
Diamonds
23

How does the experimental probability of choosing a heart compare with the theoretical probability of choosing a heart?

A) The theoretical probability of choosing a heart is StartFraction 1 over 16 EndFraction greater than the experimental probability of choosing a heart.
B) The experimental probability of choosing a heart is StartFraction 1 over 16 EndFraction greater than the theoretical probability of choosing a heart.
C) The theoretical probability of choosing a heart is StartFraction 1 over 26 EndFraction greater than the experimental probability of choosing a heart.
D) The experimental probability of choosing a heart is StartFraction 1 over 26 EndFraction greater than the theoretical probability of choosing a heart.
Mathematics
1 answer:
Artist 52 [7]2 years ago
7 0

Answer:

A) The theoretical probability of choosing a heart is 1/16 greater than the experimental probability of choosing a hear

Step-by-step explanation:

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Well you are look at a 3d image here 
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2 years ago
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Answer:

The value of the account in the year 2009 will be $682.

Step-by-step explanation:

The acount's balance, in t years after 1999, can be modeled by the following equation.

A(t) = Pe^{rt}

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$330 in an account in the year 1999

This means that P = 330

$590 in the year 2007

2007 is 8 years after 1999, so P(8) = 590.

We use this to find r.

A(t) = Pe^{rt}

590 = 330e^{8r}

e^{8r} = \frac{590}{330}

e^{8r} = 1.79

Applying ln to both sides:

\ln{e^{8r}} = \ln{1.79}

8r = \ln{1.79}

r = \frac{\ln{1.79}}{8}

r = 0.0726

Determine the value of the account, to the nearest dollar, in the year 2009.

2009 is 10 years after 1999, so this is A(10).

A(t) = 330e^{0.0726t}

A(10) = 330e^{0.0726*10} = 682

The value of the account in the year 2009 will be $682.

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2 years ago
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