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podryga [215]
1 year ago
9

A standard deck of 52 cards contains four suits: clubs, spades, hearts, and diamonds. Each deck contains an equal number of card

s in each suit. Rochelle chooses a card from the deck, records the suit, and replaces the card. Her results are shown in the table.
Cards
Suit
Observed Frequency
Clubs
29
Spades
13
Hearts
15
Diamonds
23

How does the experimental probability of choosing a heart compare with the theoretical probability of choosing a heart?

A) The theoretical probability of choosing a heart is StartFraction 1 over 16 EndFraction greater than the experimental probability of choosing a heart.
B) The experimental probability of choosing a heart is StartFraction 1 over 16 EndFraction greater than the theoretical probability of choosing a heart.
C) The theoretical probability of choosing a heart is StartFraction 1 over 26 EndFraction greater than the experimental probability of choosing a heart.
D) The experimental probability of choosing a heart is StartFraction 1 over 26 EndFraction greater than the theoretical probability of choosing a heart.
Mathematics
1 answer:
Artist 52 [7]1 year ago
7 0

Answer:

A) The theoretical probability of choosing a heart is 1/16 greater than the experimental probability of choosing a hear

Step-by-step explanation:

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A. The average yearly salary of a lawyer is $24 thousand less than twice that of an architect.
erastovalidia [21]

Answer:

The average yearly salary of  the architect is <u>$62,000</u> and the lawyer is <u>$100,000</u>.

Step-by-step explanation:

Given:

The average yearly salary of a lawyer is $24 thousand less than twice that of an architect.

Combined, an architect and a lawyer earn $ 210 thousand.

Now, to find the average yearly salary of  an architect and a lawyer.

Let the average yearly salary of  an architect be x.

So, the average yearly salary of  the lawyer = 2x-24,000.

Combined, architect and lawyer earn = \$210,000.

Now, to get the average salary of the architect and lawyer:

x+(2x-24000)=210000

x+2x-24000=210000\\\\3x-24000=210000

<em>Adding both sides 24000 we get:</em>

3x=186,000\\\\Dividing\ both\ sides\ by\ 3\ we\ get:\\\\x=62000.

<u>The average salary of architect = $62,000.</u>

Now, to get the average salary of lawyer by substituting the value of x:

2x-24000\\\\=2(62000)-24000\\\\=124000-24000\\\\=\$100,000.

<u>The average salary of lawyer = $100,000.</u>

Therefore, the average yearly salary of  the architect is $62,000 and the lawyer is $100,000.

4 0
2 years ago
Which type of statement must be proven in geometry? A. axiom
Leya [2.2K]
D a theorem needs to be proven
8 0
2 years ago
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A manageress earned £24,500 last year. This year she earns £25,235.
Korolek [52]

Answer:

Step-by-step explanation:

245000 last year

This year 25235

(y2 - y1) / y1)*100 = your percentage change

(where y1=start value and y2=end value)  

(( £25.235 - £24.500) / £24.500) * 100 = 0 %

There ain't no percentage change as there needs to be a bigger difference between the two numbers plus u should use the formula

7 0
1 year ago
Explain how you can determine the number of real number solutions of a system of equations in which one equation is linear and t
Assoli18 [71]

Answer:

To determine the number of real number solutions of as system of equations in which one equation is linear and the other is quadratic

1) Given that there are two variables, x and y as an example, we make y the subject of the equation of the linear equation and substitute the the expression for y in x into the quadratic equation

We simplify and check the number of real roots with the quadratic formula, x = \dfrac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a} for quadratic equations  the form 0 = a·x² - b·x + c

Where b² > 4·a·c there are two possible solutions and when b² = 4·a·c equation there is only one solution.

Step-by-step explanation:

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1 year ago
Ricky needs $45 to buy a jacket. He has saved $15 and plans to work as a babysitter to earn $5 per hour. Which inequality shows
inessss [21]

Answer:

Step-by-step explanation:

the answer is c

3 0
1 year ago
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