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Tpy6a [65]
1 year ago
14

A small organic food store makes two types of fruit smoothies: tropical and sport. Each tropical smoothie uses 9 oz of orange ju

ice and 6 oz of milk. Each sport smoothie uses 3 oz of orange juice and 3 oz of milk. The store stores the orange juice in a 210-oz container and milk in an 150-oz container. The store sells the tropical smoothies for $4 and sells the sport smoothie for $3. What is the maximum in sales the store can make from 1 container each of orange juice and milk?
$100

$110

$150

$280
Mathematics
2 answers:
Brilliant_brown [7]1 year ago
6 0

$150 is your answer........................................................


AlexFokin [52]1 year ago
3 0

Amount of orange juice that given container can hold = 210 -oz

Amount of milk that given container can hold = 150 -oz

1 tropical smoothie = 9 oz of orange juice + 6 oz of milk.

1 sport smoothie = 3 oz of orange juice + 3 oz of milk.

Number of packets of orange juice collected from 210 -oz for tropical smoothie if 9 -oz of orange juice is required = \frac{210}{9}=\frac{70}{3}= 23 packets (approx)

Number of packets of milk collected from 150 -oz for tropical smoothie if 6 oz of milk is required

 = \frac{150}{6}=\frac{50}{3} = 16 packets

Maximum number of Tropical smoothie= 16

Number of packets of orange juice collected from 210 -oz for sport smoothie  if 3-oz of orange juice is required =\frac{210}{3} =70 packets

Number of packets of milk collected from 210 -oz for sport smoothie  if 3 oz of milk is required =\frac{150}{3}= 50 packets

Maximum number of sport smoothie = 50

Total cost of 16 tropical smoothie , if the cost of one tropical smoothie is $ 4 = 16 × 4= $ 64

Total cost of 50 milk smoothie , if the cost of one sport smoothie is $ 3 = 50 × 3 = $ 150

The maximum  in sales the store can make from 1 container each of orange juice and milk is Sport smoothie , the total number being 50, having cost $ 150.→→→Option (C)

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Answer:

There's two ways to solve this.

Step-by-step explanation:

First way:

Let's divide the width and length by 2.3.

46÷2.3=20

69÷2.3=30

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Second Way:

Let's find the area of the actual room.

46×69

3,174 ft²

Let's find the scale drawing squared.

2.3²=5.29

3,174÷5.29

600 ft²

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2 years ago
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A teacher collected information from a class of 25 students about the time, in hours, they spent studying the previous week and
amm1812

Answer:

Correlation will not change.

Correlation coefficient = -0.72

Step-by-step explanation:

We are given the following in the question:

Correlation coefficient between hours spent studying and hours spent on the Internet = -0.72

Properties of correlation coefficient:

  • Correlation is a technique that help us to find or define a relationship between two variables.
  • It is a measure of linear relationship between two quantities.
  • It is not affected by the units of the variable or change in units of the variable.

Thus, if the units of each variable is changed from hours to minutes, the correlation coefficient remains the same between minutes studying and minutes spent on the Internet.

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2 years ago
Which decimals written in expanded form are greater than 5.3? Check all that apply. 5 + 0.3 + 0.00 5 + 0.3 + 0.001 (5 × 1) + (2
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Answer:

Any number in form of x.y = x (1) + 1/10 (y)

where x = 5 & y > 3 , or x > 5

Step-by-step explanation:

Expanded form of 5.3 = 5 (1) + 3 (1/10)

Some decimals written in expanded form that are greater than 5.3    :

5 (1) + 4 (1/10) = 5.4

6 (1) + 2 (1/10) = 6.2  

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The junior class has 50 students. Twenty-five students take only french, 15 take only Latin, and 10 take both. If a student is c
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There are 15 students who take Latin, and 10 students who take both.
Therefore:
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The answer is 1/2.
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2 years ago
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The inside diameter of a randomly selected piston ring is a random variable with mean value 13 cm and standard deviation 0.08 cm
sweet-ann [11.9K]

Answer:

a) P(12.99 ≤ X ≤ 13.01) = 0.3840

b) P(X ≥ 13.01) = 0.3075

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the cental limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 13, \sigma = 0.08

(a) Calculate P(12.99 ≤ X ≤ 13.01) when n = 16.

Here we have n = 16, s = \frac{0.08}{\sqrt{16}} = 0.02

This probability is the pvalue of Z when X = 13.01 subtracted by the pvalue of Z when X = 12.99.

X = 13.01

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{13.01 - 13}{0.02}

Z = 0.5

Z = 0.5 has a pvalue of 0.6915

X = 12.99

Z = \frac{X - \mu}{s}

Z = \frac{12.99 - 13}{0.02}

Z = -0.5

Z = -0.5 has a pvalue of 0.3075

0.6915 - 0.3075 = 0.3840

P(12.99 ≤ X ≤ 13.01) = 0.3840

(b) How likely is it that the sample mean diameter exceeds 13.01 when n = 25?

P(X ≥ 13.01) =

This is 1 subtracted by the pvalue of Z when X = 13.01. So

Z = \frac{X - \mu}{s}

Z = \frac{13.01 - 13}{0.02}

Z = 0.5

Z = 0.5 has a pvalue of 0.6915

1 - 0.6915 = 0.3075

P(X ≥ 13.01) = 0.3075

7 0
1 year ago
Read 2 more answers
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