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kozerog [31]
2 years ago
11

Which expressions are equivalent to StartFraction 1 Over 36 EndFraction? Check all that apply. 3 Superscript negative 6 6 Supers

cript negative 2 StartFraction 6 cubed Over 6 Superscript 5 EndFraction StartFraction 6 squared Over 6 Superscript negative 1 EndFraction 6 times 6 Superscript negative 2 6 Superscript negative 9 Baseline times 6 Superscript 7
Mathematics
2 answers:
atroni [7]2 years ago
6 0

Answer:

(6^3)/(6^5)

6^- 2

(6^- 9) * (6^7)

Step-by-step explanation:

3^(- 6)

= 1/3^6        (since we know that a^(- 1) = 1/a^1 = 1/a)

= 1/729

6^(- 2)

= 1/(6^2)     (since we know that a^(- 1) = 1/a^1 = 1/a)

= 1/36

6^3/6^5

= 6^(3 - 5)     (since we know if the bases are the same then powers can be manipulated like regular math problems)  

= 6^(- 2)      (since we know that a^(- 1) = 1/a^1 = 1/a)

= 1/6^2

= 1/36

6^2 / 6^(- 1)

= 6^(2 - (- 1))   (since we know if the bases are the same then powers can be manipulated like regular math problems)  

= 6^(2 + 1)

= 6^3

= 216

6*6^-2

= (6^1) * (6^- 2)

= 6^(1 - 2)

= 6^(- 1)

= 1/(6^1)    (since we know that a^(- 1) = 1/a^1 = 1/a)

= 1/6

6^(- 9) * 6^7

= 6^(- 9 + 7)  (since we know if the bases are the same then powers can be manipulated like regular math problems)  

= 6^ (- 2)     (since we know that a^(- 1) = 1/a^1 = 1/a)

= 1/6^2

= 1/36

Hope this helps, and please mark me brainliest if it does!

Elenna [48]2 years ago
5 0

Answer:

6^-2

6^3/6^5

6^-9 *6^ 7

Step-by-step explanation:

We want the fractions equal to 1/36

We know that a^-b = 1/a^b

We also know that a^b / a^c = a^(b-c)

We also know that a^b * a^c = a^(b+c)

3^ -6 = 1/3^6 = 1/729

6^-2 = 1/6^2 = 1/36

6^3/6^5 = 6^(3-5) = 6^-2 = 1/6^2 = 1/36

6^2 / 6^-1 = 6^(2- -1) = 6^3 = 216

6*6^-2 = 6^(1-2) = 6^-1 = 1/6

6^-9 *6^ 7 = 6^(-9+7) = 6^ -2 = 1/6^2 = 1/36

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5(x-4)=12 plzzz help
vivado [14]

Answer:

x=6.4

Step-by-step explanation:

5(x-4)=12

5x-20=12

add 20 from both sides

5x=32

divide 5 on both sides

x=6.4

7 0
2 years ago
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EAB and DCB are two right triangles. The figure has BED≅ BDE. Point B is the midpoint of segment AC. Prove: EAB≅ DCB
aleksklad [387]
See the attached picture. 

<span>you are given that ABCE is an isosceles trapezoid. </span>

<span>you are given that AB is parallel to EC. </span>

<span>this means that AE is congruent to BC. </span>

<span>you are given that AE and AD are congruent. </span>

<span>triangle EAD is an isosceles triangle because AE and AD are congruent. </span>

<span>this means that angle 1 is equal to angle 3. </span>

<span>since angle 1 is equal to angle 2 and angle 3 is equal to angle 1, then angle 3 is also equal to angle 2. </span>

<span>this means that AD and BC are parellel because their corresponding angles (angles 3 and 2) are equal. </span>

<span>since AB is parallel to EC and DC is part of the same line, than AB is parallel to DC. </span>

<span>you have AB parallel to DC and AD parallel to BC. </span>

<span>if opposite sides of a quadrilateral are parallel, then the quadrilateral is a parallelogram. </span>

<span>that might be able to do it,depending on whether all these statements are acceptable without proof. </span>

<span>they are either postulates or theorems that have been previously proven. </span>

<span>if not, then you need to go a little deeper and prove some of the statements that you used.. </span>

here's my diagram. 

 

<span>this is not a formal proof, but should give you some ideas about how to proceed. </span>

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5 0
2 years ago
The box which measures 70cm X 36cm X 12cm is to be covered by a canvas. How many meters of canvas of width 80cm would be require
grigory [225]

Answer:

142.2 meters.  

Step-by-step explanation:

We have been given that a box measures 70 cm X 36 cm X 12 cm is to be covered by a canvas.      

Let us find total surface area of box using surface area formula of cuboid.

\text{Total surface area of cuboid}=2(lb+bh+hl), where,

l = Length of cuboid,

b = Breadth of cuboid,

w = Width of cuboid.

\text{Total surface area of box}=2(70\cdot36+36\cdot 12+12\cdot 70)

\text{Total surface area of box}=2(2520+432+840)

\text{Total surface area of box}=2(3792)

\text{Total surface area of box}=7584

Therefore, the total surface area of box will be 7584 square cm.  

To find the length of canvas that will cover 150 boxes, we will divide total surface area of 150 such boxes by width of canvass as total surface area of canvas will also be the same.

\text{Width of canvas* Length of canvass}=\text{Total surface area of 150 boxes}

80\text{ cm}\times\text{ Length of canvass}=150\times 7584\text{cm}^2

\text{ Length of canvass}=\frac{150\times 7584\text{ cm}^2}{80\text{ cm}}

\text{ Length of canvass}=\frac{1137600\text{ cm}^2}{80\text{ cm}}

\text{ Length of canvass}=14220\text{ cm}

Let us convert the length of canvas into meters by dividing 14220 by 100 as 1 meter equals to 100 cm.

\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}

\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}

\text{ Length of canvass}=\frac{14220\text{ cm}}{100}\times\frac{m}{cm}

\text{ Length of canvass}=142.20\text{ m}

Therefore, 142.2 meters of canvas of width 80 cm required to cover 150 such boxes.

5 0
2 years ago
5 pies were shared equally among 6 girls. What fraction of a pie did each girl receive? Explain.
kompoz [17]

Answer:

Step-by-step explanation:

5/6

4 0
1 year ago
Caleb draws 14 dogs on each of 4 posters.He draws 18 cats on each of 6 other posters. If he draws 5 more dogs on each poster wit
MatroZZZ [7]
Caleb draws 14 dogs on each of 4 posters.
Then,
Number of dogs drawn by caleb in the first instance = (14 * 4) dogs
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Celeb drew 18 cats on each of 6 other posters.
Then
Number of cats drawn by Caleb in the first instance = (18 * 6) cats
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Again Caleb draws 5 more dogs on each poster with dogs.
Then,
The number of Dogs drwn in the second instance = (5 * 4) dogs
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So, the total number of dogs drawn by Caleb = ( 56 + 20) dogs
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Then the total number of cats and dogs drawn by Caleb = 108 + 76
                                                                                           = 184
5 0
2 years ago
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