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2 years ago

A snowmobile travels in a straight line.The snow-mobile’s initial velocity is +3.0 m/s.

Mathematics

2 answers:

Ipatiy [6.2K]2 years ago

7 0

A) 7 x 0.5 = 3.5 +3.0 = 6.5 m/s

B) 3/.6 = 5, it will take 5 seconds to stop

Troyanec [42]2 years ago

3 0

$v_{f}=v_{i}+at$
$v_{f}=3.0m/s+(0.50m/s^{2})(7.0s)$
$v_{f}=3+3.5=6.5m/s$

$v_{f}=v_{i}+at$
$t=\frac{v_{f}-v_{i}}{a}$
$t=\frac{0-3}{-0.6}$
$t=5sec$

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Find the cube root of 8x7x9x49x3

vodka [1.7K]

Answer:

=42

Step-by-step explanation:

The expression 8×7×9×49×3 can be written in its simplest factor form as follows.

8=2³

49=7²

9=3²

Thus the expression becomes:2³×7×3²×7²×3

Combine the indices to the same base.

2³×3³×7³

Finding the cube root involves dividing the index by three.

Thus ∛(2³×3³×7³)= 2×3×7

=42

5 0

2 years ago

Suppose that the weight of seedless watermelons is normally distributed with mean 6.1 kg. and standard deviation 1.9 kg. Let X b

horrorfan [7]

Answer:

a. $X\sim N(\mu = 6.1, \sigma = 1.9)$ b. 6.1 c. 0.6842 d. 0.4166 e. 0.1194 f. 8.5349

Step-by-step explanation:

a. The distribution of X is normal with mean 6.1 kg. and standard deviation 1.9 kg. this because X is the weight of a randomly selected seedless watermelon and we know that the set of weights of seedless watermelons is normally distributed.

b. Because for the normal distribution the mean and the median are the same, we have that the median seedless watermelong weight is 6.1 kg.

c. The z-score for a seedless watermelon weighing 7.4 kg is (7.4-6.1)/1.9 = 0.6842

d. The z-score for 6.5 kg is (6.5-6.1)/1.9 = 0.2105, and the probability we are seeking is P(Z > 0.2105) = 0.4166

e. The z-score related to 6.4 kg is $z_{1} = (6.4-6.1)/1.9 = 0.1579$ and the z-score related to 7 kg is $z_{2} = (7-6.1)/1.9 = 0.4737$ , we are seeking P(0.1579 < Z < 0.4737) = P(Z < 0.4737) - P(Z < 0.1579) = 0.6821 - 0.5627 = 0.1194

f. The 90th percentile for the standard normal distribution is 1.2815, therefore, the 90th percentile for the given distribution is 6.1 + (1.2815)(1.9) = 8.5349

7 0

2 years ago

A study was conducted on the effects of divorce. Researchers gathered data from a random sample of 5,125 adults and measured qui

shusha [124]

Answer:

We can infer a cause-and-effect relationship because multiple variables were included.

Step-by-step explanation:

The multiple attributes for the divorced ones are

1) less physically active

2) an unhealthy weight,

3) smokers.

The attribute showing the % of the married is

1) death

So when we compare the two groups married and divorced we see different variables are involved in evaluating the percentage.

This shows a cause and effect involving multiple variables.

In cause and effect one variable is dependent and the other is independent.

The cause is the independent variable and effect is the dependent variable.

CAUSE EFFECT

Married Death

Divorced 1) less physically active

2) an unhealthy weight,

3) smokers.

5 0

2 years ago

The newest model of smart car is supposed to get excellent gas mileage. A thorough study showed that gas mileage (measured in mi

Leokris [45]

Answer:

75.

Step-by-step explanation:

If the mean is 75 miles per gallon and the standard deviation is of 10 miles per gallon, it means that most values will fall between 65 and 85 miles.

The percentile 50 falls in the middle of this range, therefore, the value that represents the 50th percentile will be:

(65 +85) / 2 = 150 / 2 = 75.

4 0

2 years ago

Data from 14 cities were combined for a 20-year period, and the total 280 city-years included a total of 107 homicides. After

leonid [27]

Answer:

P(0) = 0.6825

P(1) = 0.2607

Step-by-step explanation:

From the given information, the number of homicide is 107 and the total number of homicides per city –year is 280.

Let us denote the number of homicides per city-year as X.

The mean value, X is calculated as:

\begin{array}{c}\\{\rm{Mean}} = \frac{{107}}{{280}}\\\\ = 0.382\\\end{array}

Mean= 107/280 = 0.382

The mean number of homicides per city- year \left( {\lambda = \mu } \right)(λ=μ) is 0.382.

a. The probability that zero homicides is obtained is as below:

\begin{array}{c}\\P\left( {X = 0} \right) = \frac{{{e^{ -0.382}}{{\left( {0.382} \right)}^0}}}{{0!}}\\\\ = \frac{{\left( {0.6825 \right)\left( {\rm{1}} \right)}}{1}\\\\ = 0.6825\\\end{array}

P(X=0) = e −0.382 (0.382)⁰/1

= (0.6825)(1) /1

P(X=0) = 0.6825

Thus, the probability that zero homicides P(0) is 0.6825.

b. The probability that one homicides is obtained is as below:

\begin{array}{c}\\P\left( {X = 0} \right) = \frac{{{e^{ -0.382}}{{\left( {0.382} \right)}^0}}}{{0!}}\\\\ = \frac{{\left( {0.6825 \right)\left( {\rm{1}} \right)}}{1}\\\\ = 0.6825\\\end{array}

P(X=1) = e −0.382 (0.382)¹/1

= (0.6825)(0.382)/1

P(X=1) = 0.2607

Thus, the probability that zero homicides P(0) is 0.2607.

5 0

2 years ago