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frutty [35]
2 years ago
5

Jake shows that △ △ C B A is congruent to △ △ A D C by rotating △ 180° △ C B A 180 ° around point C so it matches up with △ △ A

D C exactly. Which conclusion can be drawn from Jake's transformations?
Mathematics
1 answer:
Naddik [55]2 years ago
5 0

Answer:

Reflection about either the x- axis or y- axis.

Step-by-step explanation:

It is likely that the triangle shows a mirror image when it has been rotated at point C so that it matches ΔADC.

The triangles are congruent if the sides and angles are equal. The only way to effect the change is through a rotation.

In fact, two objects are said to be congruent if they can be transformed into another shape by translation, rotation, and reflection.

The resulting image is a distinct figure that can fit and match the other completely.

In this case, the triangle is rotated through 180⁰ so the resulting image is a reflection or mirror image.

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Two parallel lines are crossed by a transversal. What is the value of D?
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Answer:c

Step-by-step explanation:

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Explain how you can use the inscribed angle theorem to justify its second corollary, that an angle inscribed in a semicircle is
Katarina [22]
Prove:

The angle inscribed in a semicircle is a right angle. 

The inscribed angle theorem states that the angle θ, inscribed in a circle is half the measure of the central angle of the circle. So, if the given is a semi-circle, then the inscribed angle is half of 180, therefore, 90 degrees and a right angle.  <span />
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Really important please help #8
Paladinen [302]
B is the answer! Enjoy getting it correct!! :)
5 0
2 years ago
1. Dennis made a 500 km trip in five hours. For the first two hours, Dennis had an average speed of 150 km/h. For the last two h
Sati [7]

Answer:

The correct option is;

Dennis must have stopped for an hour in the middle of this trip

Step-by-step explanation:

The given parameters are;

The distance Dennis covered in 5 hours = 500 km

Dennis's average speed in the first two hours = 150 km/h

Dennis's average speed in the last two hours = 100 km/h

Therefore;

Dennis traveled 150 km/h × 2 h = 300 km in the first two hours

Dennis traveled 100 km/h × 2 h = 200 km in the last two hours

Which gives, Dennis traveled 300 km + 200 km in  2h + 2h = 4h

Therefore, Dennis traveled 500 km in 4 hours and Dennis must have stopped for an hour in the middle of this trip.

6 0
2 years ago
Cos2a.cos3a-cos2a.cos7a/sin4a.sin3a-sin2a.sin5a ​
Dmitrij [34]

Answer is -28.37

Step-by-step explanation:

from the numerator cos 2a×cos 3a - cos 2a×cos7a= cos6a^2 -cos 14a^2

= -cos8a^2 for the numerator

from the denominator;

sin4a×sin3a-sin2a×sin5a= sin12a^2 -sin10a^2

= sin2a^2

therefore, combining the equation it gives; -cos8a^2/sin2a^2

a^2 will divide each other,

= -cos8/sin2.

from the calculator,

= - 0.9903/0.0349

= -28.37

5 0
2 years ago
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