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atroni [7]
2 years ago
5

Mr. James has cylindrical beakers that measure 4 inches in diameter and are 9 inches high. What is the volume contained within t

he beakers? Use 3.14 for pi. Round your answer to the nearest hundredth. 56.52 cubic inches 100.34 cubic inches 113.04 cubic inches 226.08 cubic inches
Mathematics
2 answers:
Viefleur [7K]2 years ago
8 0

Answer:A

Step-by-step explanation:

Let me know if I helped

kirill115 [55]2 years ago
5 0
The equation to find the volume of a cylinder is V = pi•r^2•h.
The radius is half of the diameter.  Since Mr. James' beakers have a diameter of 4, their radius would be 2.  2 squared is 4.
Their height is 9 inches.
V = 3.14•4•9
V = 3.14•36
V = 113.04
The answer is C, or 113.04 cubic inches.
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Logan wants to move to a new city. He gathered graphs of temperatures for two different cities. Which statements about the data
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2 years ago
Write an integer whose absolute value is greater than itself.
raketka [301]
<span>The integer -1 has an absolute value of 1, which is greater than itself. Since all negative integers are by definition integers, their respective absolute values will be greater than themselves.</span>
3 0
2 years ago
A child wanders slowly down a circular staircase from the top of a tower. With x,y,zx,y,z in feet and the origin at the base of
babymother [125]

Answer:

a) The tower is 90 feet tall

b) She reaches the bottom at t = 18 minutes.

c) Her speed at time t is 5 \sqrt[]{5} ft/minute

d) Her acceleration at time t is 10 ft/minute^2

Step-by-step explanation:

Consider the path described by the child as going down the tower to have the following parametrization \gamma(t) = (10\cos t, 10 \sin t, 90-5t)

a) Assuming that the child is at the top of the tower when she starts going down, we have that at the initial time (t=0) we will have the value of the height of the tower. That is z = 90-5*0 = 90 ft.

b) The child reaches the bottom as soon as z =0. We want to find the value of t that does that. Then we have 0 = 90-5t, which gives us t = 18 minutes.

c) Given the parametrization we are given, the velocity of the child at time t is given by \frac{d\gamma}{dt}= (\frac{d}{dt}(10\cos t), \frac{d}{dt} (10 \sin t ), \frac{d}{dt}(90-5t)) = (-10 \sin t, 10 \cos t, -5). The speed is defined as the norm of the velocity vector,

so, the speed at time t is given by v = \sqrt[]{(-10 \sin t)^2+(10 \cos t)^2+(-5)^2} = \sqrt[]{100(\sin^2 t + \cos^2 t)+25} = \sqrt[]{125}= 5 \sqrt[]{5}

d) ON the same fashion we want to know the norm of the second derivative of \gamma.

We have that \gamma ^{''}(t) =(-10\cost t, -10 \sin t , 0) so the acceleration is given by \sqrt[]{100(\cos^2 t+ \sin^2 t )} = 10 

6 0
1 year ago
ANSWER ALL 5 PARTS.
N76 [4]
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1.a) Write the function Wa(x) representing the width of the bell pepper patch.

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\boxed{Wa(x)=\frac{x}{2}}

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<span>
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<span>
3. C</span><span>ombined area of the tomato patch and the bell pepper patch.

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</span>Aar(x)=x^{2}+\frac{x(x+2)}{2} \rightarrow Aar(x)=x^{2}+ \frac{x^{2}}{2}+x \rightarrow Aar(x)=\frac{3x^{2}}{2}+x \\ \\ \therefore \boxed{Aar(x)=\frac{x(3x+2)}{2}}
<span>
4. W</span>rite the function Aa(x) for the remaining planting area in the garden.

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</span>Aa(x)=2(x-\frac{x}{2}) \rightarrow Aa(x)=x

5. 
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Therefore the area of the remaining space is:

</span>\boxed{Aa(7.06)=7.06ft^{2}}

6 0
2 years ago
An expression is given: 2 open parentheses square root of k minus 1 close parenthesis plus square root of 8. If on adding negati
neonofarm [45]

Answer:

Possible value of k is √2

Step-by-step explanation:

The information given are;

The expression, 2·(√k - 1) + √8 to which may be added -6·√2 to obtain a rational number, we therefore have;

2·(√k - 1) + √8 - 6·√2 = R

Therefore, simplifying gives;

2·√k - 2 + 2·√2  - 6·√2 =  2·√k - 2 - 4·√2 = R

2·√k - 2 - 4·√2 + 2= R + 2 = R

2·√k - 2+ 2 - 4·√2 = R

2·√k - 2+ 2 - 4·√2 = R

2·√k + 0 - 4·√2 = 2·√k - 4·√2 = 2·(√k - 2·√2) = R

(√k - 2·√2) = R/2 = R

Therefore, √2 is a factor of √k such that √k - 2·√2 = R

Which gives k = x·√2, where x = a rational number

When x = 1, k = √2.

Therefore, a possible value of k is √2

3 0
2 years ago
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