Answer:
we need the data to answer the question
<span>The integer -1 has an absolute value of 1, which is greater than itself. Since all negative integers are by definition integers, their respective absolute values will be greater than themselves.</span>
Answer:
a) The tower is 90 feet tall
b) She reaches the bottom at t = 18 minutes.
c) Her speed at time t is 5 \sqrt[]{5} ft/minute
d) Her acceleration at time t is 10 ft/minute^2
Step-by-step explanation:
Consider the path described by the child as going down the tower to have the following parametrization 
a) Assuming that the child is at the top of the tower when she starts going down, we have that at the initial time (t=0) we will have the value of the height of the tower. That is z = 90-5*0 = 90 ft.
b) The child reaches the bottom as soon as z =0. We want to find the value of t that does that. Then we have 0 = 90-5t, which gives us t = 18 minutes.
c) Given the parametrization we are given, the velocity of the child at time t is given by
. The speed is defined as the norm of the velocity vector,
so, the speed at time t is given by ![v = \sqrt[]{(-10 \sin t)^2+(10 \cos t)^2+(-5)^2} = \sqrt[]{100(\sin^2 t + \cos^2 t)+25} = \sqrt[]{125}= 5 \sqrt[]{5}](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%5B%5D%7B%28-10%20%5Csin%20t%29%5E2%2B%2810%20%5Ccos%20t%29%5E2%2B%28-5%29%5E2%7D%20%3D%20%5Csqrt%5B%5D%7B100%28%5Csin%5E2%20t%20%2B%20%5Ccos%5E2%20t%29%2B25%7D%20%3D%20%5Csqrt%5B%5D%7B125%7D%3D%205%20%5Csqrt%5B%5D%7B5%7D)
d) ON the same fashion we want to know the norm of the second derivative of
.
We have that
so the acceleration is given by
A
function 
from a
set A to a
set B is defined as a relation that assings to each element

in the set A exactly one element

in the set B. The set A is called the domain of the function while the set B is the range. So we have five statements and need to find some functions. Melissa decides to reserve a patch in her vegetable garden for growing
bell peppers. If each side of the
tomato patch is

feet, then we have a square patch as shown in the Figure below.
1.a) Write the function Wa(x) representing the width of the bell pepper patch.
We know that she wants its width to be half the width of the tomato patch. Let

be the width of the tomato patch, then the function that matches this statement is:
1.b) Write the function La(x) representing the length of the bell pepper patch.In this case Melissa wants <span>its length to exceed the length of the tomato patch by 2 feet. To do this we enlarge the length of the tomato patch 2 feet. Therefore the function is the following:
</span>

<span>
2. Ar</span>
ea of the bell pepper patch in terms of x.
Given that the bell pepper patch is a rectangle, then t<span>he area of a rectangle is the product of the length and width. So:
</span>

<span>
3. C</span><span>
ombined area of the tomato patch and the bell pepper patch.
This function is the sum of both the area of the tomato patch and the bell pepper patch. So:
</span>

<span>
4. W</span>
rite the function Aa(x) for the remaining planting area in the garden.
The remaining planting area in the garden are the rectangles in red. So we need to subtract
the width of the bell pepper patch from the width of the tomato patch
and multiply it by 2. In mathematical language this is
given by:<span>
</span>

5. Find the area of the remaining space in the garden after planting tomatoes and bell peppers.
Given that <span>Melissa wants the area of the bell pepper patch to be 31.5 square feet, then it is true that:
</span>

<span>
Therefore the area of the remaining space is:
</span>
Answer:
Possible value of k is √2
Step-by-step explanation:
The information given are;
The expression, 2·(√k - 1) + √8 to which may be added -6·√2 to obtain a rational number, we therefore have;
2·(√k - 1) + √8 - 6·√2 = R
Therefore, simplifying gives;
2·√k - 2 + 2·√2 - 6·√2 = 2·√k - 2 - 4·√2 = R
2·√k - 2 - 4·√2 + 2= R + 2 = R
2·√k - 2+ 2 - 4·√2 = R
2·√k - 2+ 2 - 4·√2 = R
2·√k + 0 - 4·√2 = 2·√k - 4·√2 = 2·(√k - 2·√2) = R
(√k - 2·√2) = R/2 = R
Therefore, √2 is a factor of √k such that √k - 2·√2 = R
Which gives k = x·√2, where x = a rational number
When x = 1, k = √2.
Therefore, a possible value of k is √2