Answer:
The probability that a particular driver had exactly two speeding violations is 0.009.
Step-by-step explanation:
We are given that a sample of 2,000 licensed drivers revealed the following number of speeding violations;
<u>Number of Violations</u> <u>Number of Drivers</u>
0 1,910
1 46
2 18
3 12
4 9
5 or more <u> 5 </u>
<u>Total</u> <u> 2000 </u>
<u />
Now, the data means that 1,910 drivers had 0 speeding violations and so on.
Now, we have to find the probability that a particular driver had exactly two speeding violations, that means;
Number of drivers having exactly two speeding violations = 18
Total numbers of drivers = 2000
So, the required probability =
=
= <u>0.009</u>
G(h) h
12 3
8 5
4 7
0 9
Equation of the line:
slope = [12-0]/[3-9] = 12 / -6 = -2
g / [h - 9] = -2
g = -2(h-9)
g = -2h + 18
g = 18 -2h
Filling the tank ==> h = 0
g = 18 - 2(0) = 18
Answer: first option g = 18 -2 h; 18
I believe Z=18
Example:
2/3z + 1 = 13
Multiply both sides: 2/3z * 3 + 1 * 3 = 13 * 3
Refine: 2/3z + 3 = 39
Subtract from both sides: 2z + 3 - 3 = 39 - 3
Refine: 2z=36
2z/2 = 36/12
Z=18