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Anit [1.1K]
2 years ago
7

Mrs. Johnson buys 2 chickens. The average weight of the 2 chickens is 4 pounds. One of the chickens is 2 pounds heavier. What is

the weight of the heaviest chicken?
Mathematics
2 answers:
irakobra [83]2 years ago
7 0
Heaviest chicken is 6 pounds
saul85 [17]2 years ago
4 0
The heaviest chicken would actually be 4 pounds. Since the average of both chickens is 4, that means they had to do the weight of the chickens added together than divided by two. The only one that would work is 2. So then you add 2 to that and it would be four.
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Find the variance of 101, 102, 100, 100, 110, 109, 109, 108, 109
Andreyy89
101, 102, 100, 100, 110, 109, 109 ,108, 109 average to 105.3



subtracting the mean from each number yields the below-

-4,-3,-5,-5,5,4,4,3,4



Squaring each number gives-

16,9,25,25,16,16,9,16



The average of these numbers is 12.89 to two decimal places, so your variance is 12.89
6 0
2 years ago
What is the value of the expression i 0 × i 1 × i 2 × i 3 × i 4?
astraxan [27]
ANSWER


The value of the expression is
- 1


EXPLANATION

Method 1: Rewrite as product of
{i}^{2}


The expression given to us is,

{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}


We use the fact that
{i}^{2}  =  - 1
to simplify the above expression.



{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  =  {i}^{0}  \times {i}^{1}  \times {i}^{3}   \times {i}^{2}   \times {i}^{4}


This implies,


{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  =  {i}^{0}  \times {i}^{2}  \times {i}^{2}   \times {i}^{2}   \times {i}^{2} \times {i}^{2}


We substitute to obtain,

{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  =  1\times  - 1 \times  - 1  \times  - 1\times  - 1 \times  - 1


{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  =  1\times  1 \times   1  \times  - 1 =  - 1


Method 2: Use indices to solve.



{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  = {i}^{0 + 1 + 2 + 3 + 4}



This implies that,


{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  = {i}^{10}




{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  =  (  {{i}^{2}} )^{5}


{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  =  (   - 1 )^{5}   =  - 1


8 0
2 years ago
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ch4aika [34]

i think the answer is letter C

5 0
2 years ago
A grocery store sells an 18 ounce container of peanut butter for $3.28. What is the cost per ounce (unit price)?
AnnyKZ [126]
Here,
cost of 18 ounce container of peanut butter = $3.28
cost of 1 ounce container of peanut butter = $3.28/18
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7 0
2 years ago
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A high school coach needs to buy new athletic shorts for the 15 members of the basketball team. The coach must spend less than $
AfilCa [17]
If the budget is $200 and he have 15 members then we have divide the two. 200 / 15 = $13.33 per shorts. 15x =< $200. x represents 13.33. So the solution represents the coach may spend up to $13.33 per pair of shorts. If it was even 1 cent more than $13.33 than he wouldn't have enough.So he can spend up to $13.33 or less per pair of shorts.
5 0
2 years ago
Read 2 more answers
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