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shtirl [24]
2 years ago
5

Solve for x: 3 over 3 x plus 1 over quantity x plus 4 equals 10 over 7x .

Mathematics
1 answer:
77julia77 [94]2 years ago
6 0
There is one<span> last step after getting </span>x<span> = </span>3<span>. You must check </span>x<span> = </span>3<span> in the original equation to be sure that </span>x<span> = </span>3<span> does not cause a zero denominator.</span>
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Which system is equivalent y=-2x^2 y=x-2
german
The wording of your question suggests that there were answer choices.  Mind sharing them?

The system   <span>y=-2x^2 y=x-2 would be best written as:

</span><span>y=-2x^2 
y=x-2                  If you subst. x-2 for y in the first equation, you'll get:
                           x-2 = -2x^2,   or 2x^2 + x - 2 = 0.
                           </span>
7 0
1 year ago
Read 2 more answers
A random sample of 20 individuals who graduated from college five years ago were asked to report the total amount of debt (in $)
Gekata [30.6K]

Answer:

a. As college debt increases current investment decreases.

b. Y= 68778.2406 - 1.9112X

Every time the college debt increases one dollar, the estimated mean of the current investments decreases 1.9112 dollars.

c. There is a significant linear relationship between college debt and current investment because the P-value is less than 0.1.

d. Y= $59222.2406

e. R²= 0.9818

Step-by-step explanation:

Hello!

You have the information on a random sample of 20 individuals who graduated from college five years ago. The variables of interest are:

Y: Current investment of an individual that graduated from college 5 years ago.

X: Total debt of an individual when he graduated from college 5 years ago.

a)

To see the relationship between the information about the debt and the investment is it best to make a scatterplot with the sample information.

As you can see in the scatterplot (attachment) there is a negative relationship between the current investment and the debt after college, this means that the greater the debt these individuals had, the less they are currently investing.

The statement that best describes it is: As college debt increases current investment decreases.

b)

The population regression equation is Y= α + βX +Ei

To develope the regression equation you have to estimate alpha and beta:

a= Y[bar] -bX[bar]

a= 44248.55 - (-1.91)*12829.70

a= 68778.2406

b= \frac{sumXY-\frac{(sumX)(sumY)}{n} }{sumX^2-\frac{(sumX)^2}{n} }

b=\frac{9014653088-\frac{(256594)(884971)}{20} }{4515520748-\frac{(256594)^2}{20} }

b= -1.9112

∑X= 256594

∑X²= 4515520748

∑Y= 884971

∑Y²= 43710429303

∑XY= 9014653088

n= 20

Means:

Y[bar]= ∑Y/n= 884971/20= 44248.55

X[bar]= ∑X/n= 256594/20= 12829.70

The estimated regression equation is:

Y= 68778.2406 - 1.9112X

Every time the college debt increases one dollar, the estimated mean of the current investments decreases 1.9112 dollars.

c)

The hypotheses to test if there is a linear regression between the two variables are two tailed:

H₀: β = 0

H₁: β ≠ 0

α: 0.01

To make this test you can use either a Student t or the Snedecor's F (ANOVA)

Using t=<u>  b - β  </u>=<u>  -1.91 - 0  </u>= -31.83

                 Sb         0.06

The critical region and the p-value for this test are two tailed.

The p-value is: 0.0001

The p-value is less than the level of signification, the decision is to reject the null hypothesis.

Using the

F= \frac{MSTr}{MSEr}= \frac{4472537017.96}{4400485.72} =1016.37

The rejection region using the ANOVA is one-tailed to the right, and so is the p-value.

The p-value is: 0.0001

Using this approach, the decision is also to reject the null hypothesis.

The conclusion is that at a 1% significance level, there is a linear regression between the current investment and the college debt.

The correct statement is:

There is a significant linear relationship between college debt and current investment because the P-value is less than 0.1.

d)

To predict what value will take Y to a given value of X you have to replace it in the estimated regression equation.

Y/X=$5000

Y= 68778.2406 - 1.9112*5000

Y= $59222.2406

The current investment of an individual that had a $5000 college debt is $59222.2406.

e)

To estimate the proportion of variation of the dependent variable that is explained/ given by the independent variable you have to calculate the coefficient of determination R².

R^2= \frac{b^2[sumX^2-\frac{(sumX)^2}{n} ]}{sumY^2-\frac{(sumY)^2}{n} }

R^2= \frac{-1.9112^2[4515520748-\frac{(256594)^2}{20} ]}{43710429303-\frac{(884971)^2}{20} }

R²= 0.9818

This means that 98.18% of the variability of the current investments are explained by the college debt at graduation under the estimated regression model: Y= 68778.2406 - 1.9112X

I hope it helps!

5 0
1 year ago
Identify which of the statements is true. −36.5 &gt; −36.07 −2.6 &gt; 2.521 −8.0329 &gt; −8.045 −0.4 &gt; −0.004
max2010maxim [7]
For the numbers with negative sign, the larger the numerical value following the negative sign, the lower is the value of the number. The symbol, ">" means "greater than". 

From the inequalities given above, the one that makes exact sense is,
     -8.0329 > -8.045

Hence, the answer to this item is the third choice. 
7 0
2 years ago
After learning the midpoint construction Sally realizes that she could determine one fourth the length of a segment how could sh
Viefleur [7K]
The midpoint of two points is the point which divides the line segment joining the two points into two equal parts.

Suppose, we have a line segment AB with a point C, between point A and point B such that the distance AC is equal to the distance CB, then we say that point C is the midpoint of line AB.

Suppose, we have another point D between point A and point C, such that the distance AD is equal to the distance DC, then we say that point D is the midpoint of AC.

Notice that point D is a fourth of line segment AB.

Thus, AD is <span>one fourth the length of segment AB.

Therefore, one fourth the length of a segment can be obtained by evaluating the midpoint of the midpoint of the line segment.
</span>
7 0
2 years ago
The table below gives the dimensions of a bridge and a scale model of the bridgeFind the scale factor of the model to the real b
Oksana_A [137]
The corresponding sides of the model and the actual bridge are in proportion because the two solids are similar.

The scale factor from the model to the actual bridge is 5/25 = 6/30 = 8/40 = 1/5.

Answer:  1/5
3 0
1 year ago
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