The new crew works at the rate 1/12 apt/hr.
The old crew works at the rate 1/6 apt/hr.
Let x = hours required to paint the apartment when the two crews work together.
That is,
(1/12 + 1/6 apt/hr)*(x hr) = (1 apt)
(3/12)x = 1
(1/4)x = 1
x = 4 hours
Answer: 4 hours
Answer:
The solution proves that the equation has a non-trivial solution.
Step-by-step explanation:
We want to show that the equation has nontrivial solutions for which 
Let
be a set of non-zero numbers such that that 
Because T is a linear solution:

= 
= 
= 
= 
= 0
This shows that
are linearly independent with the mapping resulting in a non-trivial solution.
Don't you just grab the volume of the box and subtract the volume of the basketballs.
Answer:
100
Step-by-step explanation:
The function takes in an X value and produces a Y value.
The Y value equals 24 times the X value plus 4 more.
This means that:
Y = 24X + 4
When the X value equals 4, the Y value will be:
Y = 24(4) + 4
Y = 96 + 4
Y = 100
When the X value is 4, the Y value is 100.
A decagon has 10 sides.
It it is regular you can build 10 isosceles triangles from the center of the decagon to the 10 sides.
Each triangle has a common vertex where the angle of each triangle is 360° / 10 = 36°.
So each time that you rotate the decagon a multiple of 36° around the center you get an image that coincides with the original decagon.
If the letters are given clockwise:
- when you rotate 36° counter clockwise, the point A' (the image of A) will coincide with the point J.
- when you rotate 72° (2 times 36°) counter clockwise, the point A' will land on I.
- when you rotate 108° (3 times 36°) counter clockwise, the point A' will land on H.
- when you rotate 144° (4 times 36°) counter clockwise, the point A' will land on G.
- when you rotate 180° (5 times 36°) counter clockwise, the point A' will land on I.
- when you rotate 216° (6 times 36°) counter clockwise, the point A' will land on E.
- whn you rotate 252° (7 times 36°) counterclockwise, the point A' will coincide with D.
Add other 36° each time and A' will coincide successively with C, B and the same A.