Event: Probability: A. Too much enamel 0.18 B. Too little enamel 0.24 C. Uneven application 0.33 D. No defects noted 0.47
let P(AC) = x, P(BC) = y, then P(A) + P(B) + P(C) - (x+y) = 1-0.47 = 0.53 x+y = 0.22
3. The probability of paint defects that results to <span>an improper amount of paint and uneven application? </span>
P(A U B U C) = 0.53
4. <span>the probability of a paint defect that results to</span>
<span>the proper amount of paint, but uneven application?</span>
P(C) - P(AC) - P(BC) = 0.47 - 0.22 = 0.25
A and B are disjoint so P(ABC) = 0, but you can have P(AC) and P(BC). you can't compute these separately here, but you can compute P(AC) + P(BC). By the way, P(AC) eg is just an abbreviated version of P(A∩C).
Answer:
The number of 7th students on the Jackson Middle School basketball teams is 17 and the number of 8th students on the Jackson Middle School basketball teams is 36
Step-by-step explanation:
Let
x ----> the number of 7th students on the Jackson Middle School basketball teams
y ----> the number of 8th students on the Jackson Middle School basketball teams
we know that
There are 53 students on the Jackson Middle School basketball teams
so
-----> equation A
The number of 8th graders is 15 fewer than three times the number of 7th graders
so
----> equation B
substitute equation B in equation A

solve for x

Find the value of y

therefore
The number of 7th students on the Jackson Middle School basketball teams is 17 and the number of 8th students on the Jackson Middle School basketball teams is 36
Let x be unknown number. If number x is multiplied by
and the product is equal to
then

To find x you should divide
by

Answer: 
Answer:
y= - 1/2 (negative half) = -0.5
Step-by-step explanation:
−6y+3(12y)=20(y−1)+15
Multiply 3 and 12 to get 36.
−6y+36y=20(y−1)+15
Combine −6y and 36y to get 30y.
30y=20(y−1)+15
Use the distributive property to multiply 20 by y−1.
30y=20y−20+15
Add −20 and 15 to get −5.
30y=20y−5
Subtract 20y from both sides.
30y−20y=−5
Combine 30y and −20y to get 10y.
10y=−5
Divide both sides by 10
y= -5/10
Reduce the fraction -5/10 = -0.5 to lowest terms by extracting and cancelling out 5 .
P(both poodle) = (3/10)(3/10) = 9/100
Answer: The probability of choosing the same puppy is 9/100