Answer:
Step-by-step explanation:
I'm not sure I understand the problem, but I think it's this:
Dr North Piegans practice sees 125 cats. In 2010, 24.8% of cats were classified as obese, compared to 21.6% in 2011, what is the
1 answer:
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Answer:
When x = 15, y= 2
When y= 10, x= 3
Step-by-step explanation:
This is a question in inverse proportion. In this proportion, an increase in one quantity would lead to a decrease in the other and vice versa.
We are to complete the table using the relationship between x and y.
Given:
y is inversely proportional to x = y ∝ 1/x
∝ = proportional to
y ∝ 1/x
y = k × 1/x
Where k = constant of proportionality
To understand the relationship between y and x, we need to find the value of k.
y = k × 1/x
From the table,
When x = 6, y = 5
5 = k × 1/6
5 = k/6
k = 6×5 = 30
y = 30 × 1/x
y = 30/x
The above relationship would enable us find the missing parts.
When x = 15, y= ?
y = 30/15
y = 2
When y= 10, x= ?
10 = 30/x
10x = 30
x = 30/10
x= 3
Answer:
A and C
Step-by-step explanation:
To determine which events are equal, we explicitly define the elements in each set builder.
For event A
A={1.3}
for event B
B={x|x is a number on a die}
The possible numbers on a die are 1,2,3,4,5 and 6. Hence event B is computed as
B={1,2,3,4,5,6}
for event C
Hence the set c is C={1,3}
and for the set D {x| x is the number of heads when six coins re tossed }
In the tossing a six coins it is possible not to have any head and it is possible to have head ranging from 1 to 6
Hence the set D can be expressed as
D={0,1,2,3,4,5,6}
In conclusion, when all the set are compared only set A and set C are equal