Question

5r^2-44r+120 = -30r+11r

Answer 1

$5r^2-44r+120 = -30r+11r \\ \\ 5f^2 - 44r + 120 = -19r \\ \\ 5r^2 - 44r + 120 + 19r = 0 \\ \\ 5r^2 - 25r + 120 = 0 \\ \\ r = \frac{25+5 \sqrt{71i} }{10} , \frac{25-5 \sqrt{71i} }{10} \\ \\ r = \frac{5+ \sqrt{71i} }{2} , \frac{5 - \sqrt{71i} }{2} \\ \\ ANSWER: r = \frac{5+ \sqrt{71i} }{2} , \frac{5 - \sqrt{71i} }{2}$