Ask question

Ask question

All categories

1 year ago

12

Roy's average balance checking account pays simple interest of 4.8% annually and he made $2.25 in interest last month. What was

Roy's average balance last month? A. 56.25 B. 5.63 C. 562.50 D. 5625.00

1 answer:

Leona [35]1 year ago

5 0

Answer:

It’s 5625.00 don’t listen to this other one

Step-by-step explanation:

You might be interested in

Which transformation causes the described change in the graph of the function y = cos x?

tia_tia [17]

A: a horizontal shrink would be caused by cos 3x.
B: a vertical stretch would be caused by 3 cos x
C: a horizontal stretch would be caused by cos (1/3)x
D: a vertical shrink would be caused by 1/3 cos x.

4 0

1 year ago

Read 2 more answers

a recipe uses 1 1/4 cups of milk to make 10 servings. if the same amount of milk is used for each serving, how many servings can

Anestetic [448]

Answer:

128 servings can be made using 1 gallon of milk.

Step-by-step explanation:

Given that:

$1\frac{1}{4}$ cups of milk make 10 servings

$1\frac{1}{4}$ can also be written as 1.25

Ratio of cups of milk to servings = 1.25 : 10

1 gallon = 16 cups

Let,

x be the number of servings made from 1 gallon

Ratio of cups of milk to servings = 16 : x

This is a direct proportion

1.25 : 10 :: 16 : x

Product of mean = Product of extreme

10*16 = 1.25x

160 = 1.25x

1.25x=160

Dividing both sides by 1.25

$\frac{1.25x}{1.25}=\frac{160}{1.25}\\x=128$

Hence,

128 servings can be made using 1 gallon of milk.

3 0

1 year ago

Exams are approaching and Helen is allocating time to studying for exams. She feels that with the appropriate amount of studying

svp [43]

Answer: 0.05

Step-by-step explanation:

Let M = Event of getting an A in Marketing class.

S = Event of getting an A in Spanish class,

i.e. P(M) = 0.80 , P(S) = 0.60 and P(M∩S)=0.45

Required probability = P(neither M nor S)

= P(M'∩S')

= P(M∪S)' [∵P(A'∩B')=P(A∪B)']

=1- P(M∪S) [∵P(A')=1-P(A)]

= 1- (P(M)+P(S)- P(M∩S)) [∵P(A∪B)=P(A)+P(B)-P(A∩B)]

= 1- (0.80+0.60-0.45)

= 1- 0.95

= 0.05

hence, the probability that Helen does not get an A in either class= 0.05

3 0

2 years ago

Tickets to a musical cost $30 for adults and $12 for children. At one particular performance 960 people attended and $19 080 was

postnew [5]

In order to solve this, you have to set up a systems of linear equations.

Let's say that children = c and adults = a

30a + 12c = 19,080
a + c = 960

I'm going to show you how to solve this system of linear equations by substitution, the easiest way to solve in my opinion.

a + c = 960
- c - c
---------------------- ⇒ Step 1: Solve for either a or c in either equation.
a = 960 - c

20(960 - c)+ 12c = 19,080
19,200 - 20c + 12c = 19,080
19,200 - 8c = 19,080
- 19,200 - 19,200
---------------------------------- ⇒ Step 2: Substitute in the value you got for a or c
8c = -120 into the opposite equation.
------ ---------
8 8

c = -15

30a + 12(-15) = 19,080
30a - 180 = 19,080
+ 180 + 180
-------------------------------
30a = 19,260
------- -----------
30 30

a = 642
__________________________________________________________

I just realized that there can't be a negative amount of children, so I'm sorry if these results are all wrong.

7 0

2 years ago

Read 2 more answers

Here is a flower made up of yellow hexagons, red trapezoids, and green triangles. How many copies of this flower pattern could y

olganol [36]

Answer:

Part a) You could build 5 copies of the flower pattern

Part b) You would have 40 red trapezoids left over

Step-by-step explanation:

The complete question in the attached figure

Part a)

Let

x -----> the number of yellow hexagons

y ----> the number of red trapezoids

z ----> the number of green triangles

we know that

The flower pattern has the following ratios

$\frac{x}{y}=\frac{6}{2} ---->\frac{x}{y}=3 ----> \text {equation A}$

$\frac{x}{z}=\frac{6}{9} -->\frac{x}{z}=\frac{2}{3} --> \text {equation B}$

$\frac{y}{z}=\frac{2}{9} ------> \text {equation C}$

Find out how many copies of this flower pattern could you build if you had 30 yellow hexagons,50 red trapezoids, and 60 green triangles

1) For x=30

Divide 30 by 6 (remember that in one pattern there are 6 yellow hexagons)

$30/6=5\ copies$

Verify the quantity of y needed and the quantity of z needed

Find the value of y

$\frac{30}{y}=3 ---->y=30/3=10\\$

10 < 50 ----> is ok

Find the value of z

$\frac{30}{z}=\frac{2}{3} ---> z=30*3/2=45$

45<60 --->is ok

2) For y=50

Divide 50 by 2 (remember that in one pattern there are 2 red trapezoids)

$50/2=25\ copies$

Verify the quantity of x needed and the quantity of z needed

Find the value of x

$\frac{x}{50}=3 ---->x=50*3=150$

150 > 30 ----> is not ok

3) For z=60

Divide 60 by 9 (remember that in one pattern there are 9 green triangles)

60/9=6.7 copies

Round down

6 copies -----> 6(9)=54 green triangles

Verify the quantity of x needed and the quantity of y needed

Find the value of x

$\frac{x}{54}=\frac{2}{3} ---> z=54*2/3=36$

36> 30 --->is not ok

therefore

You could build 5 copies of the flower pattern

Part b)

we know that

x:y:z=6:2:9

If you build 5 copies

1) You would use 5*6=30 yellow hexagons and you would have 0 hexagons left over

2) You would use 5*2=10 red trapezoids and you would have (50-10=40) trapezoids left over

3) You would use 5*9=45 green triangles and you would have (60-45=15) triangles left over

therefore

You would have 40 red trapezoids left over

4 0

1 year ago