Ask question

Ask question

All categories

Maksim231197 [3]

2 years ago

10

Three cats and three dogs, A, B, C, D, E, and F, live on a street in three different-coloured houses. Each house hosts one cat a

nd one dog. One house is red. A is a cat and does not live in the red house. B is a dog and does not live in the same house as C (even though they could). D lives in the blue house. D does not live with A or F (even though it could). E does not live with A and does not live in the yellow house.
Indicate whether each letter correspond to a cat or a dog, and match each cat and each dog with a colored house.

1 answer:

vaieri [72.5K]2 years ago

5 0

Answer:

1) A is a cat; B is a dog; C is a cat; D is a dog; E is a dog; F is a cat

2) A lives with B in a yellow house; C lives with D in a blue house; E lives with F in a red house.

Step-by-step explanation:

Step 1: First we identify the animals as cats or dogs

A is a cat

B is a Dog

Since B can live with C, C is a cat

Since D can live with A, D is a dog

F is a cat since it can live with D

E is therefore, a dog

Step 2: We then identify the house each two animals live in pairs of a cat and a dog

D lives in a blue house

A lives in a yellow house since it does not live with D or in a red house

C lives with D in a blue house since D does not live with either A or F

E lives in a red house since it does not live with A or in a yellow house

F lives with E in a red house since E does not live with A

Therefore, B lives with A in a yellow house

You might be interested in

A has the coordinates (–4, 3) and B has the coordinates (4, 4). If DO,1/2(x, y) is a dilation of △ABC, what is true about the im

fomenos

A dilation is a transformation $D_{o,k}(x,y)$ , with center O and a scale factor of k that is not zero, that maps O to itself and any other point P to P'. The center O is a fixed point, P' is the image of P, points O, P and P' are on the same line.

In a dilation of $D_{o, \frac{1}{2} }(x,y)$ , the scale factor, $\frac{1}{2}$ is mapping the original figure to the image in such a way that the distances from O to the vertices of the image are half the distances from O to the original figure. Also the size of the image is half the size of the original figure.

Therefore, <span>If $D_{o, \frac{1}{2} }(x,y)$ is a dilation of △ABC, the truth about the image △A'B'C'</span> are:

<span>AB is parallel to A'B'.

$D_{o, \frac{1}{2} }(x,y)=( \frac{1}{2}x, \frac{1}{2}y)$

The distance from A' to the origin is half the distance from A to the origin.</span>

3 0

2 years ago

Read 2 more answers

Explain how you can use the inscribed angle theorem to justify its second corollary, that an angle inscribed in a semicircle is

Katarina [22]

Prove:

The angle inscribed in a semicircle is a right angle.

The inscribed angle theorem states that the angle θ, inscribed in a circle is half the measure of the central angle of the circle. So, if the given is a semi-circle, then the inscribed angle is half of 180, therefore, 90 degrees and a right angle. <span />

6 0

2 years ago

Read 2 more answers

A function, h(x), is defined as shown. h(x) = StartLayout Enlarged left-brace 1st row 1st column one-fourth x minus 4, 2nd colum

oee [108]

Answer:

The correct answer is Graph B.

Hope this helps!!! :)

8 0

2 years ago

Read 2 more answers

Olivia had math and reading homework tonight. Olivia can solve each math problem in 1 minute and she can read each page in 1.5 m

ziro4ka [17]

Answer: the system of equations are

x + y = 22

x + 1.5y = 30

Step-by-step explanation:

Let x represent the number of math problems that Olivia solved.

Let y represent the number of pages that Olivia read.

Olivia completed a total of 22 math problems and pages of reading. This means that

x + y = 22- - - - - - - - - - - - - - -1

Olivia can solve each math problem in 1 minute and she can read each page in 1.5 minutes. Olivia completed a total of 22 math problems and pages of reading in 30 minutes. This means that

x + 1.5y = 30 - -- - - - - - - - - -2

8 0

2 years ago

Which test point holds true for y − 2x ≤ 1?

CaHeK987 [17]

So in order to find the correct answer, we can just easily plug in the values to check which ordered pair matches the given inequality above. So based on my solutions, the correct answer would be the last pair.
<span> y − 2x ≤ 1
0 - 2(5)</span> ≤ 1
0-10 ≤ 1
-10 ≤ 1
Hope this answer helps.

3 0

2 years ago