Answer:
the first and last one apply
Step-by-step explanation:
just did it on edu
Answer:
Step-by-step explanation:
There are 950 students at Hanover High School. The ratio of the number of freshmen to all students is 3:10. This means that the number of freshmen is 3/10 × total number of students.
Number of freshmen = 3/10×950 =285 freshmen
The ratio of the number of sophomore to all students is 1:2. This means that the number of sophomore is 1/2 × total number of students.
Number of sophomore = 1/2×950 =475 sophomore
The ratio of the number of freshmen to sophomore is the number of freshmen/ the number of
sophomore.
It becomes 285/475 = 57/95
Dilation refers to a non rigid motion where a figure is transform and its image has the same form but a different size measure.
On this exercise is asked to find the scale factor by which the triangle ABC was
dilated to produce the triangle A'B'C'.
Dilation is define by the rule (x,y)-- (kx, ky) where k represents the scale factor.
As can be see on the picture the dilation produce was an enlargement meaning that the image is larger that the preimage.
Of this form you can discard the choices A and B as possible solutions.
Lets try 5/2 as the possible scale factor:
(x,y)-- (kx, ky)
A(0,2)--(5/2(0),5/2(2))=A'(0,5)
B(2,2)--(5/2(2),5/2(2))=B'(5,5)
C(2,0)--(5/2(2),5/2(0))=C'(5,0)
Lets try 5/1 or 5 as the scale factor:
A(0,2)--(5(0),5(2))=A'(0,10)
B(2,2)--(5(2),5(2))=B'(10,10)
C(2,0)--(5(2),5(0))=C'(10,0)
As said at the beginning of the question the triangle was not only dilated.
After a dilation and a translation, the scale factor of the dilation is letter C or 5/2.
Answer:
2
Step-by-step explanation:
Given g(x) = sin(x)-1/cos2(x), we are to find the limit if the function g(x) as g(x) tends to π/2
Substituting π/2 into the function
lim x-->π/2 sin(x)-1/cos 2(x)
= sin(π/2) - 1/cos(2)(π/2)
= 1 - 1/cosπ
= 1- 1/-1
= 1 -(-1)
= 1+1
= 2
Hence the limit of the function h(x) = sin(x)-1/cos2(x) as x--> π/2 is 2
Answer:
477
Step-by-step explanation:
Given that:
Number of trials (n) = 500
Mean (m) = 0
Standard deviation (s) = 1
how many readings fall within +/- 2.000 deg F of the mean value
Mean of 0 and standard deviation of 1
P(-2 ≤ x ≤ 2)
Using the Z probability calculator :
P(x ≤ 2) = 0.97725 ;
P(x ≤ - 2) = 0.02275
Hence :
P(x ≤ 2) - P(x ≤ - 2) = 0.97725 - 0.02275 = 0.9545
Hence, number of readings in 500 trials:
0.9545 * 500 = 477.25
= 477 values