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2 years ago

Name the similar triangles. ΔABC ~ ΔDEF ΔABC ~ ΔEFD ΔABC ~ ΔDFE ΔABC ~ ΔFED

Mathematics

1 answer:

IgorLugansk [536]2 years ago

7 0

Triangle ABC because the other ones are different from each other and there is only one of them.

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When two pipes fill a pool together, they can finish in 5 hours. If one of the pipes fills half the pool then the other takes ov

Alexxandr [17]

♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫

➷The answer is 18 hours.

Explanation: If you look carefully, you can see that the answer is the second condition as well. If one pipe did half, then the other pipe took over and that took 18 hours, that means that it equals one pipe filling the pool continuously by itself. :)

✽

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

DOGE

3 0

2 years ago

Vanna is saving for a trip. The hotel room will be $298.17 for 3 nights, and there will be additional fees. What is her daily co

docker41 [41]

Answer:

Step-by-step explanation:

Total cost for the three nights

Total_3 = $298.17 + 3*u

Where <em>u </em>represents the unknown fees for a single day

To find the daily cost, we divide the previous equation by three

Daily cost = ($298.17 + 3*u)/3

Daily cost = ($99.39 + u)

So, if we create an inequality for the daily cost

Let x = Daily cost

x > $99.39

She will pay more than $99.39 per night

7 0

2 years ago

Researchers studying catfish estimated the number of fingerling catfish and large catfish living in different rivers throughout

Keith_Richards [23]

Answer:

The correct answer to the question is

C) The mean and range of the fingerling catfish are both greater than those of the large catfish.

Step-by-step explanation:

From the attached chart and table, it is seen that the mean = (∑ f×m)/n

Where Mean x = Mean estimate of frequency distribution

f = Class frequency

m = midpoint of each class

∑ f×m = the sum of the product of each midpoint value and its respective frequency

n = The sum of the frequencies

Therefore from the tables we have

For the Fingerling catfish

(∑ f×m)/n = 11037.5/1.375 = 8027.3

and the range = (Maximum value) - (minimum value) in the data set

= 10500 - 3500 = 7000

For the Large catfish we have

(∑ f×m)/n = 2931.25/2.1 = 1395.83

and the range = (Maximum value) - (minimum value) in the data set

= 2125 - 375 = 1750

As seen above, the mean and range of the fingerling catfish are both greater than those of the large catfish

8 0

2 years ago

Select the two statements that are true about the equation y−56=4(x+5)y-56=4(x+5).

Sergio [31]

The correct answers are:

The slope of the line is 4.

A point on the line is (−5, 56)

Step-by-step explanation:

Given equation is:

$y-56=4(x+5)$

The slope-intercept form is:

$y-y_1=m(x-x_1)$

Comparing both equations we get

m = 4

$y-56=y-y_1\\y_1 = 56\\x+5 = x-x_1\\x_1=-5$

The point is (-5,56)

So, the correct answers are:

The slope of the line is 4.

A point on the line is (−5, 56)

Keywords: Point-slope form, Slope

Learn more about point-slope form at:

#LearnwithBrainly

6 0

2 years ago

The amount of a sample remaining after t days is given by the equation P(t)=A(1/2)^(t/h), where A is the initial amount of the s

s344n2d4d5 [400]

The equation is:
P ( t ) = A * (1/2 )^(t/h)
If a sample contains 18% of the original amount of Radon - 222 and h = 3.8:
0.18 * A = A * ( 0.5 )^(t/3.8) / : A ( we will divide both sides of the equation by A )
0.18 = ( 0.5 )^(t/3.8)
$t/3.8 = log _{1/2}0.18$
t / 3.8 = 2.47 ≈ 2.5
t = 3.8 * 2.5 = 9.5
Answer:
The best estimate for the age of the sample is 9.5 days.

5 0

2 years ago

Read 2 more answers

Name the similar triangles.￼ ΔABC ~ ΔDEF ΔABC ~ ΔEFD ΔABC ~ ΔDFE ΔABC ~ ΔFED​

Name the similar triangles. ΔABC ~ ΔDEF ΔABC ~ ΔEFD ΔABC ~ ΔDFE ΔABC ~ ΔFED