Answer: The correct option is (B) 3.
Step-by-step explanation: We are given a circle X with radius 5 units and chord AB with length 8 units.
We are to find the length of segment XC that bisects chord.
We know that the line segment drawn from the center of a circle to the midpoint of a chord is perpendicular to the chord.
So, in the given circle X, the segment XC is perpendicular to chord AB. Then, triangle XCB will be a right angled triangle with hypotenuse XB.
Since XC bisects AB, so the length of BC will be

And, radius, XB = 5 units.
Using Pythagoras theorem in triangle XCB, we have

Thus, the length of the segment XC is 3 units.
Option (B) is CORRECT.
Answer:
The score that separates the lower 5% of the class from the rest of the class is 55.6.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question:

Find the score that separates the lower 5% of the class from the rest of the class.
This score is the 5th percentile, which is X when Z has a pvalue of 0.05. So it is X when Z = -1.645.


The score that separates the lower 5% of the class from the rest of the class is 55.6.
Answer:
it's d
Step-by-step explanation:
because they can't go over 1128 but they can equal or not
The given data is the following:
Student Trial 1 Trial 2 Trial 3 Average
----------- -------- -------- -------- ------------
1 66.0 66.5 68.5 67.0
2 67.5 64.0 70.5 67.3
3 60.3 60.5 60.5 61.0
4 55.0 58.0 59.0 57.3
Let us check the reported averages.
Student 1:
Average = (66.0 + 66.5 + 68.5)/3 = 67.0 Correct
Student 2:
Average = (67.5 + 64.0 + 70.5)/3 = 67.3 Correct
Student 3:
Average = (60.3 + 60.5 + 60.5)/3 = 604 Incorrect
Student 4:
Average = (55.0 + 58.0 + 59.0)/3 = 57.3 Correct
Answer: Student 3