Answer:
a) density of the object is 3995.01, b) the weight scale reads 22N c) the sum individually will be the same with when added together.
Step-by-step explanation:
The weight of the object in air is 8N,
and weight = Mass * acceleration due to gravity = m * 9.81
8/9.81 = 0.815,
upthrust( force acting on the body from the liquid impeding the immersion) on the body when fully submerged = weight in air - weight in water = 8N - 6N =2N
Upthrust = weight of water displaced = 2N = mass * acceleration
2/9.81 = 0.204kg
density of water(1000kg/m^3) = mass of water / volume of water
volume of water displaced = 0.204/1000 = 0.000204m^3 (204cm^3)
volume of water displaced = volume of the solid
density of solid = mass/ volume = 0.815/0.000204 = 3995.01kg/m^3
b) when fully submerge in water the the scale experience according to newton third law of motion ( equal and opposite reaction of forces) additional 2N push so that total weight with the fully submerge solid = 20N + upthrust = 20N + 2N =22N
c) the of two scale reading is before (8N + 20N = 28N) and after (6N + 22N = 28) since there is no loss of matter; the demonstration was in equilibrium.
Answer:
Step-by-step explanation:
erasers=e
pencils=p
3e+5p=7.55 ...(1)
6e+12p=17.40
divide by 2
3e+6p=8.70 ...(2)
(2)-(1) gives
p=8.70-7.55=1.15
from (1)
3e+5(1.15)=7.55
3e+5.75=7.55
3e=7.55-5.75
3e=1.80
e=1.80/3=0.60
cost of 1 eraser=$0.60
cost of 1 pencil =$1.15
Answer:
Step-by-step explanation:
a.) The worst-case height of an AVL tree or red-black tree with 100,000 entries is 2 log 100, 000.
b.) A (2, 4) tree storing these same number of entries would have a worst-case height of log 100, 000.
c.) A red-black tree with 100,000 entries is 2 log 100, 000
d.) The worst-case height of T is 100,000.
e.) A binary search tree storing such a set would have a worst-case height of 100,000.
Answer:
The Correct Statement is
• Use the distance formula to prove the lengths of the opposite sides are the same.
Step-by-step explanation:
The statement explains how you could use coordinate geometry to prove the opposite sides of a quadrilateral are congruent is,
• Use the distance formula to prove the lengths of the opposite sides are the same.
Distance Formula is given by
For Parallel Lines:
Use the slope formula to prove the slopes of the opposite sides are the same.
For Perpendicular Lines:
Use the slope formula to prove the slopes of the opposite sides are opposite reciprocals.
