Answer:
1/9
Step-by-step explanation:
135 in Sport centre: Total
59:swimming pool
31:track
19 both swimming and gym
16 gym and track
4 all three facilities
4 people use all three facilities, then
16 - 4 = 12 people use the gym and the track and do not use the pool;
9 - 4 = 5 people use the pool and the track and do not use the gym;
19 - 4 = 15 people use the gym and the pool and do not use the track.
At least two facilities use 4 + 12 + 5 + 15 = 36 people, 4 of them use all three facilities. Thus, the probability that a randomly selected person which uses at least two facilities, uses all the facilities is
4/36=1/9
Hope this helps!!!
Let us assume the cost of a soft drink = x dollars
Value of the gift certificate that Angela had = $5
Cost of the movie ticket = $10
Cost of a medium popcorn = $5.50
Then
27.90 + 5 = 2(10) + 2(5.50) + x
32.90 = 20 + 11 + x
32.90 = 31 + x
x = 1.90 dollars
From the above deduction, it can be easily concluded that the correct option among all the options that are given in the question is the first option or $1.90.
<span>5x²y + 2xy² + x²y
Combining like terms would be
6x²y + 2xy²
The two terms are now unique and cannot be combined any further. </span><span>
</span>
For this question you would have to expand the numbers to the thounsandths
so it can be 9.181, 9.182, 9.183 and so on
Let s represent number of shirts and h represent number of hats.
We have been given that the organizers of a talent show have budgeted $1800 to buy souvenir clothing to sell at the event. They can buy shirts for $10 each and hats for $8 each.
The cost of s shirts would be 
and cost of h hats would be 
. The cost of s shirts and h hats should be less than or equal to 1800. We can represent this information in an inequality as:
We are also told that organizers plan to buy at least 5 times as many shirts as hats. This means that number of shirts should be greater than or equal to 5 times hats. We can represent this information in an inequality as:
Therefore, the second inequality should be and option C is the correct choice.
