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n200080 [17]
2 years ago
12

A private plane is traveling due east at a rate of 160 mph. A south wind is blowing 30 mph. What is the actual velocity of the p

lane?
A. ≈ 157 mph
B. ≈ 190 mph
C. ≈ 130 mph
D. ≈ 163 mph

Mathematics
1 answer:
photoshop1234 [79]2 years ago
8 0

The resultant velocity of the plane is the sum of the two velocity vectors which are perpendicular to each other. See the attached figure.

The magnitude of the resultant velocity is

\sqrt{160^2+30^2}= \sqrt{26500}=162.79 \;mph.

The approximate value of the actual velocity of the plane is 163 \;mph. Correct choice is (D).

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Seth is using the figure shown below to prove the Pythagorean Theorem using triangle similarity: In the given triangle PQR, angl
Naily [24]

Answer:

Part A: \triangle RPQ \sim \triangle RSP

Part B. All angles are same, so the triangles are similar.  

Part C. RP = 8

Step-by-step explanation:

We are given a right angled triangle \triangle RPQ with \angle P = 90^\circ.

PS is perpendicular to the hypotenuse RQ of \triangle RPQ and S lies on RQ.

Part A:

To identify the pair of similar triangles.

\triangle RPQ \sim \triangle RSP.

Part B:

To identify the type of similarity.

Kindly refer to the image attached in the answer area.

Let us consider the triangles \triangle RPQ \ and\ \triangle RSP.

\angle RSP =\angle RPQ =90^\circ

Also, \angle R is common to both the triangles under consideration.

Now, we can see that two angles of two triangles are equal.

So, third angle of the two triangles will also be same.

i.e. All three angles of two triangles \triangle RPQ \ and\ \triangle RSP are equal to each other.

So, by A-A-A (Angle - Angle - Angle) similarity, we can say that \triangle RPQ \sim \triangle RSP.

Part C:

RS = 4

RQ = 16, Find RP.

There is one property of similar triangles that:

The ratio of corresponding sides of two similar triangles is equal.

i.e.

\dfrac{RS}{RP} = \dfrac{RP}{RQ}\\\Rightarrow RP ^2 = RS \times RQ\\\Rightarrow RP ^2 = 4 \times 16\\\Rightarrow RP ^2 = 64\\\Rightarrow \bold{RP = 8\ units}

5 0
2 years ago
What are the solutions for the equation 2cos0+1=0 ?
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Answer:

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proved

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2 years ago
3) Margarita manejó 429 km: 42 en la ciudad y el resto, en la autopista.
12345 [234]

Answer:

Margarita gastó <u>$40.43.</u>

Step-by-step explanation:

Tenemos la siguiente información.

<u>km recorridos por Margarita</u>

42 km - ciudad

387 km - autopista

<u>Rendimiento del carro</u>

1 galon cada 28 km - ciudad

1 galon cada 36 km - autopista

Hacemos el siguiente factor de conversión

<u>Ciudad</u>

42 km \times \frac{1\: galon}{28\: km}=1.5\: galones

<u>Autopista</u>

387 km \times \frac{1\: galon}{36\: km}=10.75\: galones

Ahoa, se sabe que 1 galon cuesta $3.30. Por lo tanto, el costo de viaje será:

Total galones = 1.5 + 10.75 = 12.25 galones

Total costo = 3.30*12.25 = $40.43.

Espero te haya servido!

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The number of tropical fish that an aquarium can hold depends on the volume of the fish tank. the interior dimensions of the fis
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