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2 years ago

Which is equivalent to RootIndex 3 StartRoot 8 EndRoot Superscript x?

Mathematics

1 answer:

sergeinik [125]2 years ago

8 0

Solving RootIndex 3 StartRoot 8 EndRoot Superscript x we get $=2^x$

Step-by-step explanation:

We need to find equivalent to RootIndex 3 StartRoot 8 EndRoot Superscript x

Writing in mathematical form:

$(\sqrt[3]{8})^x$

Solving:

We know 8= 2x2x2= 2^3

and $\sqrt[3]{x}=x^{\frac{1}{3}}$

Applying these rules:

$=((2^3)^{\frac{1}{3}})^x$

$=(2^{\frac{3}{3}})^x\\$

$=2^x$

So, solving RootIndex 3 StartRoot 8 EndRoot Superscript x we get $=2^x$

Keywords: Radical Expression

Learn more about Radical Expression at:

#learnwithBrainly

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An automated egg carton loader has a 1% probability of cracking an egg, and a customer will complain if more than one egg per do

vaieri [72.5K]

Answer:

a) Binomial distribution B(n=12,p=0.01)

b) P=0.007

c) P=0.999924

d) P=0.366

Step-by-step explanation:

a) The distribution of cracked eggs per dozen should be a binomial distribution B(12,0.01), as it can model 12 independent events.

b) To calculate the probability of having a carton of dozen eggs with more than one cracked egg, we will first calculate the probabilities of having zero or one cracked egg.

$P(k=0)=\binom{12}{0}p^0(1-p)^{12}=1*1*0.99^{12}=1*0.886=0.886\\\\P(k=1)=\binom{12}{1}p^1(1-p)^{11}=12*0.01*0.99^{11}=12*0.01*0.895=0.107$

Then,

$P(k>1)=1-(P(k=0)+P(k=1))=1-(0.886+0.107)=1-0.993=0.007$

c) In this case, the distribution is B(1200,0.01)

$P(k=0)=\binom{1200}{0}p^0(1-p)^{12}=1*1*0.99^{1200}=1* 0.000006 = 0.000006 \\\\ P(k=1)=\binom{1200}{1}p^1(1-p)^{1199}=1200*0.01*0.99^{1199}=1200*0.01* 0.000006 \\\\P(k=1)= 0.00007\\\\\\P(k\leq1)=0.000006+0.000070=0.000076\\\\\\P(k>1)=1-P(k\leq 1)=1-0.000076=0.999924$

d) In this case, the distribution is B(100,0.01)

We can calculate this probability as the probability of having 0 cracked eggs in a batch of 100 eggs.

$P(k=0)=\binom{100}{0}p^0(1-p)^{100}=0.99^{100}=0.366$

5 0

2 years ago

The formula for the area (A) of a circle is A = π • r2, where r is the radius of the circle. Ronisha wants to find the area of a

kobusy [5.1K]

<em>Greetings from Brasil...</em>

Here we will apply rule of 3...

This formula, A = πR², its for the whole circle, that is, 360° (2π)

We want the area of only a part, that is, a circular sector whose angle π/6

sector area

2π ----- πR²

π/6 ----- X

2πX = (π/6).πR²

2πX = π²R²/6

X = π²R²/12π

If Ronisha multiply the area by 1/12 she will get the area of sector with angle of π/6

6 0

2 years ago

A football quarterback enjoys practicing his long passes over 40 yards. He misses the first pass 40% of the time. When he misses

dangina [55]

Answer:

8% or 0.08

Step-by-step explanation:

Probability of missing the first pass = 40% = 0.40

Probability of missing the second pass = 20% = 0.20

We have to find the probability that he misses both the passes. Since the two passes are independent of each other, the probability that he misses two passes will be:

Probability of missing 1st pass x Probability of missing 2nd pass

i.e.

Probability of missing two passes in a row = 0.40 x 0.20 = 0.08 = 8%

Thus, there is 8% probability that he misses two passes in a row.

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2 years ago

Read 2 more answers

The rectangular playground in tim's school is three times as long as it is wide. the area of the playground is 75 square meters.

qwelly [4]

Let x be the width of the playground, then 3x is the length of the
<span>playground

х * 3х = 75
3x</span>² = 75
x² = 25
x = 5 m (width)
5*3=15 m (length)

Perimeter = 2(5+15) = 2*20 = 40 meters.

8 0

2 years ago

An octopus weighted 5/6 kilogram. After two weeks, it's weight has increased by 3/10 kilogram. But afterwards, it lost 1/5 kilog

Alex777 [14]

Answer

14/15 kg

Step-by-step explanation:

Rewriting our equation with parts separated

=1+215−15

Solving the fraction parts

2/15−15=?

Find the LCD of 2/15 and 1/5 and rewrite to solve with the equivalent fractions.

LCD = 15

2/15−3/15=−1/15

Combining the whole and fraction parts

1−1/15=14/15

Solution by Formulas

converting mixed numbers to fractions, our initial equation becomes,

17/15−15

Applying the fractions formula for subtraction,

=(17×5)−(1×15)15×5

=85−15/75

=70/75

Simplifying 70/75, the answer is

=14/15

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2 years ago