-4 = 8m + 18n
-18n = 8m + 4
/-18 /-18 /-18
n = 8m/-18 + 4/-18
I'm not sure so yeah
Answer:
The ultra-marathon Idita Rod Trail is about 38 times longer than the Boston Marathon.
Step-by-step explanation:
Let
x -----> the length of the Boston Marathon in meters
y -----> the length of the Idita rod Trail Invitational ultra-marathon in meters
we have


we know that
To find out how many times as long is the course of the Idita rod Trail ultra-marathon as that of the Boston Marathon, divide the length of the Idita rod Trail Invitational ultra-marathon by the length of the Boston Marathon
so


Remember that
To divide two numbers in scientific notation, divide their coefficients and subtract their exponents

therefore
The ultra-marathon Idita Rod Trail is about 38 times longer than the Boston Marathon.
Add the order of pizzas together and divide by four. Round your answer.
Resultant Vector: 554 N in the angle 80 degrees with the horizontal.
First, we must put each given in Polar form:
1. 500 N in the angle of 35 degrees with the horizontal
2. 400 N in the angle of 140 degrees with the horizontal in the same direction of the first guy wire (counterclockwise direction)
Then, add up the two polar forms, and it would give 553.59 in the angle of 79.26 with horizontal- counterclockwise direction. As estimated, 554 N in the direction of 80 degrees North of East.
Answer:
MArginal productivity: 
We can interpret this as he will reduce his time an <em>additional </em>0.0002 seconds for every <em>additional </em>yard he trains.
Step-by-step explanation:
The marginal productivy is the instant rate of change in the result for an increase in one unit of a factor.
In this case, the productivity is the time he last in the 100-yard. The factor is the amount of yards he train per week.
The marginal productivity can be expressed as:

where dt is the variation in time and dL is the variation in training yards.
We can not derive the function because it is not defined, but we can approximate with the last two points given:

Then we can interpret this as he will reduce his time an <em>additional </em>0.0002 seconds for every <em>additional </em>yard he trains.
This is an approximation that is valid in the interval of 60,000 to 70,000 yards of training.