What you can use for this case is a function of the potential type.
We have then
y = a (b) ^ x
Where we have:
Walker starts the fund by depositing $ 5
a = 5
Each week the balance of the fund is twice the balance of the previous week:
b = 2
The function is:
y = 5 (2) ^ x
The number of weeks to reach $ 1280 is 8 weeks.
Check:
y = 5 (2) ^ 8
y = 1280
Answer:
An equation can be used to find the number of weeks, x, after which the balance of the fund will reach $ 1,280 is:
y = 5 (2) ^ x
The number of weeks that it takes to reach the class goal is
8 weeks
Answer:
The answer is below
Step-by-step explanation:
The question is not complete, what are the coordinates of point Q and R. But I would show how to solve this.
The location of a point O(x, y) which divides line segment AB in the ratio a:b with point A at (
) and B(
) is given by the formula:

If point Q is at (
) and S at (
) and R(x, y) divides QS in the ratio QR to RS is 3:5, The coordinates of R is:

Let us assume Q(−9,4) and S(7,−4)

Answer:
Volume=355 cm³
Step-by-step explanation:
I assume it should be 10 cm, not 10 m. If it is 10 m, everything will have to be adjusted.
Circumference = 2
r
10=2
r
10÷2
=r
1.59=r
V=
r²h
V=
(1.59)(71)
v=355
Gallons per day.......gallons / day.....so u put the gallons over the number of days, then divide
(1/2) / 6 = 1/2 * 1/6 = 1/12 of a gallon per day <==
Answer:
The area of the shaded region is 42.50 cm².
Step-by-step explanation:
Consider the figure below.
The radius of the circle is, <em>r</em> = 5 cm.
The sides of the rectangle are:
<em>l</em> = 11 cm
<em>b</em> = 11 cm.
Compute the area of the shaded region as follows:
Area of the shaded region = Area of rectangle - Area of circle
![=[l\times b]-[\pi r^{2}]\\\\=[11\times 11]-[3.14\times 5\times 5]\\\\=121-78.50\\\\=42.50](https://tex.z-dn.net/?f=%3D%5Bl%5Ctimes%20b%5D-%5B%5Cpi%20r%5E%7B2%7D%5D%5C%5C%5C%5C%3D%5B11%5Ctimes%2011%5D-%5B3.14%5Ctimes%205%5Ctimes%205%5D%5C%5C%5C%5C%3D121-78.50%5C%5C%5C%5C%3D42.50)
Thus, the area of the shaded region is 42.50 cm².