Answer:
B) 2
Step-by-step explanation:
There are 2 points of intersection
X-3y=6
x+y=2
this is an substitution problem
so first you can do is rewrite the problem by subjection one variable
x=3y+6
then substitute this in the other proble
x+y=2
(3y+6)+y=2
4y+6=2
4y=2-6
4y=-4
y=-1
then substitute the no. in the original equation.
x=3y+6
x=3(-1)+6
x=-3+6
x=3
now you got the intercepts and you draw the line and check.
it's in the IV quadrant
Answer:
Answer: (2a - 5 + b)5
Answer: 10 x (a - 2.5 + 0.5b)
Answer: (-2a + 5 - b) ⋅ (-5)
I think they all apply (tick all the statements) since a rigid transformation doesn’t affect the shape of the triangle simply it’s position.
Hello,
y=5+3*cos (2(x-π/3))
The function is periodic with periode=2π.
-1<=cos (2(x-π/3))<=1
==>-1*3<=3*cos (2(x-π/3))<=3*1
==>5-3<=5+3cos(2(x-π/3))<=5+3
==>2<= y<=8