Answer:

Step-by-step explanation:
Given that from a well shuffled set of playing cards (52 in number) a card is drawn and without replacing it, next card is drawn.
A - the first card is 4
B - second card is ace
We have to find probability for

P(A) = no of 4s in the deck/total cards = 
After this first drawn if 4 is drawn, we have remaining 51 cards with 4 aces in it
P(B) = no of Aces in 51 cards/51 = 
Hence

(Here we see that A and B are independent once we adjust the number of cards. Also for both we multiply the probabilities)
Add some of them or all of them to your sum of 47.75, if either or exceeds the limit then that is what left out.
Alrighty, so, if I remember correctly: For the first question you have 20 possible outcomes, 4 of which are multiples of 5. (5,10,15,20). This gives you 4/20, I multiplied both the numerator and denominator by 200 which then gave me 800/4000. Next I divided which gave me 0.2.