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yan [13]
1 year ago
5

Subtract 5x2 - 7x - 6 from 9x2 + 3x – 4.

Mathematics
1 answer:
andrezito [222]1 year ago
7 0
-7x+4 i’m not sure if it’s correct but i hope it is. sorry if it’s not
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In a certain country, a letter up to 1 ounce requires postage in the amount of $0.42, and each additional ounce (or fraction of
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The answer is $7.14 is wunt josiah pay
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Ephemeral services corporation (esco) knows that nine other companies besides esco are bidding for a $900,000 government contrac
EastWind [94]

Answer:

c. $100,000

Step-by-step explanation:

Calculation of the expected net profit of Ephemeral services corporation

Since we are been told that 9 other companies besides esco are as well bidding for the $900,000 government contract, it means we have to find the expected net profit by dividing 1 by 9×$900,000 .Thus ESCO can only expect to cover its sunk cost.

Hence ,

E(X) = (1/9) × $900,000

E(X)=0.111111111×$900,000

E(X)= $100,000

Therefore the expected net profit would be $100,000

4 0
1 year ago
A trampoline salesman makes $25,000 annually plus 6% commission on his total sales. If he sold $40,000 worth of trampolines this
Katarina [22]

Multiply sales by 6%

40,000 x 0.06 = 2,400

Add that to his base pay:

2400 + 25000 = $27,400 total pay.

5 0
1 year ago
Kay buys 12 pounds of apples. Each pound costs $3.if she gives the cashier two $20 bills, how much change should she receive.
zlopas [31]

12 pounds x $3 = $36

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7 0
1 year ago
A town has a population of 5000 and grows 3.5% every year. To the nearest tenth of a year, how long will it be until the populat
oksano4ka [1.4K]

Answer:

Step-by-step explanation:

This is an exponential function. In order to find the answer to the question, we need to first determine what the equation is that models this information. The standard form for an exponential function is

y=a(b)^x where a is the initial value and b is the growth/decay rate. If the starting population is 5000, then

a = 5000

If the population is growing, that means that it retains 100% of the initial population and is added to by another 3.5%. So in a sense the population grows 100% + 3.5% = 103.5% or, in decimal form, 1.035. So

b = 1.035

Our function is

y=5000(1.035)^x where y is the ending population and x is the number of years it takes to get to that ending population. We want to know how long, x, it will be til the population reaches 7300, y.

7300=5000(1.035)^x and we need to solve for x. The only way to do that is by using logs. I'll use natural logs for this.

Begin by dividing both sides by 5000 to get

1.46=1.035^x and take the natural log of both sides:

ln(1.46)=ln(1.035)^x

The power rule for natural logs is that we can now bring the exponent down in front of the ln to get:

ln(1.46)=xln(1.035) To solve for x, we now divide both sides by ln(1.035):

\frac{ln(1.46)}{ln(1.035)}=x

Do that division on your calculator and get that

x = 11.0 years.

That means that 11 years after the population was 5000 it will be expected to reach 7300 (as long as the growth rate remains 3.5%)

5 0
2 years ago
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