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vivado [14]
2 years ago
9

Thomas invested $8,500 for one year. Part of the money was invested at6% and the rest at 9%. The total interest earned was $667.

50. How much did Thomas invest at the 6% rate?
Mathematics
1 answer:
oee [108]2 years ago
4 0
Okay so say that x=amount invested with 6% and y=amount invested with 9%
x+y=8,500 so > x=8500-y
6%=0.06        <span>9%=0.09</span>
0.06x +0.09y=667.5 (Substitute in x=8500-y so only numbers and y)
0.06(8500-y)+0.09y=667.5 (expand brackets)
510-0.06y+0.09y=667.5 (-510)
0.03y=117.5 (/0.03)
$3916.67=Y  ->9%
X=8500-Y 
x=$4583.33 ->6%
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Answer:

Step-by-step explanation:

50 - 31 = 19

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4 0
1 year ago
What are the real zeros of the function g(x) = x^3 + 2x^2 − x − 2?
PSYCHO15rus [73]
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6 0
2 years ago
Read 2 more answers
Estimate the indicated probability by using normal distribution as an approximation to the binomial distribution. Estimate P(6)
lianna [129]

Answer:

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Step-by-step explanation:

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Mean = np

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Standard Deviation =\sqrt{npq} = \sqrt{(18)(0.3)(0.7)}  

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Z = ( of successes we're interested in - Mean) ÷ (Standard Deviation)

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5 0
1 year ago
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NemiM [27]
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7 0
2 years ago
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xxTIMURxx [149]
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