Ask question

Ask question

All categories

2 years ago

8

The rule below shows how Mrs. Rousseau's long-distance phone company computes her monthly bill. Which answer expresses that rule

in the form of an equation? Multiply the number of minutes Mrs. Rousseau spent on long-distance calls by $0.42, the long-distance rate. Then add $24, the flat monthly charge.

1 answer:

Ludmilka [50]2 years ago

4 0

So then n=number of long distance calls, then add the flat rate

long distance cost=number of calls times cost per clll or n times 0.42 or 0.42n
the flat rate is 24

so total is c so
c=24+0.42n

You might be interested in

The function D(t) defines a traveler's distance from home, in miles, as a function of time, in hours. D(t) = StartLayout enlarge

nalin [4]

- At 2 hours, the traveler is 725 miles from home.

- At 3 hours, the distance is constant, at 880 miles. --> TRUE.

- The total distance from home after 6 hours is 1,062.5 miles --> TRUE.

Step-by-step explanation:

The function D(t) is defined as follows:

$D(t) = 300t+125$ for $t< 2.5$

$D(t) = 880$ for $2.5 \leq 3.5$

$D(t) = 75t+612.5$ for $t\leq 6$

Where

t is the time in hours

D(t) is the distance covered, in miles, after t hours

Now let's analyze the different statements:

- The starting distance, at 0 hours, is 300 miles. --> FALSE. In fact, if we substitute t = 0 into the 1st equation, we get

$D(0) = (300)(0)+125 = 125$

So, the distance at t = 0 is 125 miles.

- At 2 hours, the traveler is 725 miles from home. --> TRUE. In fact, if we substitute t = 2 into the 1st equation,

$D(2) = (300)(2)+125 = 725$

- At 2.5 hours, the traveler is 875 miles from home. --> FALSE. In fact, for t=2.5 we have to use the 2nd equation, which states that the distance is:

D(t) = 880

So, not 875 miles.

- At 3 hours, the distance is constant, at 880 miles. --> TRUE. This is clearly visible from the 2nd equation: for t between 2.5 and 3.5 (so, in this case), the distance is

D(t) = 880

- The total distance from home after 6 hours is 1,062.5 miles --> TRUE. In fact, if we replace t = 6 into the last equation,

$D(6)) = 75(6)+612.5=1062.5$

Learn more about functions:

brainly.com/question/3511750

brainly.com/question/8243712

brainly.com/question/8307968

Learn more about distance:

brainly.com/question/3969582

#LearnwithBrainly

4 0

2 years ago

Read 2 more answers

Which statement shows how two polynomials 4x + 6 and 2x2 − 8x demonstrate the closure property when multiplied?

steposvetlana [31]

Answer:

$8x^{3} -20x^{2} -48x$ is a polynomial

Step-by-step explanation:

Given : polynomials $4x+6$ and $2x^{2} -8x$

Solution:

$(4x+6)*(2x^{2} -8x)$

$4x(2x^{2} -8x)+6(2x^{2} -8x)$

$8x^{3} -32x^{2}+12x^{2} -48x$

$8x^{3} -20x^{2} -48x$

Polynomial :An expression of more than two algebraic terms, especially the sum of several terms that contain different powers of the same variable.

Thus $8x^{3} -20x^{2} -48x$ is a polynomial

Hence option A is correct.

7 0

2 years ago

Read 2 more answers

Amala listed her assets and liabilities. Credit Card Balance Car (Paid in full) Jewelry Student Loan Savings Account Stocks $850

MakcuM [25]

Answer:

Total of Amala’s liabilities is $5500 .

Step-by-step explanation:

Liabilities is defined as the sums of money which it owes .

As given

Amala listed her assets and liabilities. Credit Card Balance Car (Paid in full) Jewelry Student Loan Savings Account Stocks $850 $2,200 $125 $2,500 $1,200 $1,500 .

As Credit card balance , car (Paid in full) and student loan are Amala liabilities .

Thus

Total amount of Amala’s liabilities = Credit card balance + car + student loan .

Putting all the values in the above

Total amount of Amala’s liabilities = 850 + 2200 + 2500

= $5500

Therefore the total of Amala’s liabilities is $5500 .

4 0

2 years ago

Read 2 more answers

Which statement correctly describes the characterization in this excerpt? Indirect characterization is used to show that Steve i

Alexandra [31]

Answer:

The answer is B

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

What is the following simplified product? Assume x greater-than-or-equal-to 0 (StartRoot 10 x Superscript 4 Baseline EndRoot min

9966 [12]

Answer:

$\bold{10x^4\sqrt{6}+x^3\sqrt{30x}-10x^4\sqrt{3}-x^3\sqrt{15x}}$

Step-by-step explanation:

To find:

Simplified product of:

$(\sqrt{10x^4}-x\sqrt{5x^2})(2\sqrt{15x^4}+\sqrt{3x^3})$

Solution:

First of all, let us have a look at some of the formula:

1. $(a+b) (c+d) = ac+bc+ad+bd$

2. $a^b\times a^c =a^{b+c }$

3. $\sqrt{a^{2b}} = \sqrt{a^b.a^b}=a^b$

4. $\sqrt a \times \sqrt b = \sqrt{a\times b}$

Now, let us apply the above formula to solve the given expression.

$(\sqrt{10x^4}-x\sqrt{5x^2})(2\sqrt{15x^4}+\sqrt{3x^3})\\\\\Rightarrow(\sqrt{10x^4})(2\sqrt{15x^4})+(\sqrt{10x^4})(\sqrt{3x^3})-(x\sqrt{5x^2})(2\sqrt{15x^4})-(x\sqrt{5x^2})(\sqrt{3x^3})\\\\\Rightarrow2\sqrt{150x^8}+\sqrt{30x^7}-2x\sqrt{75x^6}-x\sqrt{15x^5}\\\\\Rightarrow\bold{10x^4\sqrt{6}+x^3\sqrt{30x}-10x^4\sqrt{3}-x^3\sqrt{15x}}$

The answer is:

$\bold{10x^4\sqrt{6}+x^3\sqrt{30x}-10x^4\sqrt{3}-x^3\sqrt{15x}}$

8 0

2 years ago