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o-na [289]
2 years ago
6

Four friends are playing a game. They randomly choose a handful of marbles from a bag. The player with the highest ratio of blue

marbles to purple marbles gets to go first.
Number of Marbles

Name

Blue Marbles

Purple Marbles

Rosa

10

12

Chi

5

6

Alberto

5

12

Pedro

10

6


Which player gets to go first?

Rosa

Chi

Alberto

Pedro
Mathematics
2 answers:
salantis [7]2 years ago
7 0

Answer: (D)

Step-by-step explanation: Pedro.

Monica [59]2 years ago
4 0

We are given the number of Blue and Purple Marbles for each of the four friends. So first we have to find the ratio of blue marbles to purple marbles for each of them.

A) Rosa

Number of blue marbles = 10

Number of purple marbles = 12

Ratio of blue to purple marbles = \frac{10}{12}=0.833

B) Chi

Number of blue marbles = 5

Number of purple marbles = 6

Ratio of blue to purple marbles = \frac{5}{6}=0.833

C) Alberto

Number of blue marbles = 5

Number of purple marbles = 12

Ratio of blue to purple marbles = \frac{5}{12}=0.417

D) Pedro

Number of blue marbles = 10

Number of purple marbles = 6

Ratio of blue to purple marbles = \frac{10}{6}=1.667

From the above calculations we can see that Pedro has the highest value of ratio for blue marbles to purple marbles. Also we can see Pedro is the only one for whom the number of blue marbles is more than the number of purple marbles. So this confirms that our calculation is correct.

Thus, the player which gets to go first is Pedro.

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Company F sells fabrics known as fat quarters, which are rectangles of fabric created by cutting a yard of fabric into four piec
jeka94

Answer:

a) Y 0 1 2

P(Y) 0.58 0.23 0.11

b) mean= 0.45, S.D= 0.6718

c) mean= 1.285, S.D= 8.74

Step-by-step explanation:

a) The following table shows the probability distribution of X:

X 0 1 2 3 4 or more

P(X) 0.58 0.23 0.11 0.05 0.03

Defect >2 = cannot be sold

Y = the number of defects on a fat quarter that can be sold by Company F.

Y = defect that can be sold

Y = Defect less or equal to 2 = 0,1,2

Probability distribution of the random variable Y:

Y 0 1 2

P(Y) 0.58 0.23 0.11

b) mean of Y (μ)

μ = Σ x*P(Y)

= (0*0.58) +(1*0.23)+(2*0.11)

= 0+0.23+0.22 = 0.45

Standard deviation of Y = σ

σ = Σ√(x-mean)^2*P(Y)

= Σ√[(x- μ )^2*P(Y)]

= √[(0-0.45)^2*0.58+ (1-0.45)^2*0.23 + (2-0.45)^2*0.11]

= √[0.11745 + 0.069575 +0.264275

= √(0.4513

σ = 0.6718

Company G:

σ for defect that be sold = 0.66

μ for defect that be sold = 0.40

Difference between μ of F and μ of G

= 0.45-0.40 = 0.05

Difference between σ of F and σ of G

= 0.67-0.66 = 0.01

Selling price of fat quarter without defect = $5

Discount per defect = $1.5

Selling price per defect = 5-1.5 = $3.5

Discount per 2 defect = $1.5*2 = $3

Selling price per defect = 5-3 = $2

Since defect to be sold cannot be greater than 2, let Y = 5,3,2

Probability distribution of the selling price Y:

Y 5 3 2

P(Y) 0.58 0.23 0.11

μ = (5*0.58) +(3.5*0.23)+(2*0.11)

μ = 2.9+0.805+0.22 =1.285

σ = Σ√[(x- μ )^2*P(Y)]

σ = √[(5-1.285)^2*0.58+ (3-1.285)^2*0.23 + (2-1.285)^2*0.11]

σ = 8.00+0.68+0.06 = 8.74

7 0
2 years ago
The time it takes to deliver a pizza (from time of phone call to delivery at door) follows a normal distribution with a mean (µ)
Yuki888 [10]

Answer:

99.87% of the store’s total delivery orders will be delivered to consumers with charge

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 45, \sigma = 5

If a pizza store’s policy is, "Orders delivered within one hour or they’re free!", what percentage of the store’s total delivery orders will be delivered to consumers with charge?

Within one hour, which is 60 minutes. So this is the pvalue of Z when X = 60.

Z = \frac{X - \mu}{\sigma}

Z = \frac{60 - 45}{5}

Z = 3

Z = 3 has a pvalue of 0.9987

99.87% of the store’s total delivery orders will be delivered to consumers with charge

5 0
2 years ago
Sameera predicted that she would sell 38 blankets, but she actually sold 28 blankets. Which expression would find the percent er
antoniya [11.8K]

Solution: We are given:

Predicted Sales by Sameera =38

Actual Sales by Sameera =28

Now to find the Percent error, we have to use the below formula:

Percent-Error= \frac{|Predicted-value - Actual-value|}{Actual-value} \times 100 \%

                       =\frac{|38-28|}{28} \times 100 \%

                       =\frac{10}{28}\times 100 \%

                       =35.71 \%

Therefore, the percent error is 35.71 \%      

8 0
2 years ago
Read 2 more answers
The height of two similar pails are 12cm and 8cm.The larger pail can hold 2litres. What is the capacity of the smaller pail?
Vedmedyk [2.9K]

Answer:

1.33 liters

Step-by-step explanation:

Volume of any shape is given by cross sectional area multiplied by height. Therefore, V=Ah

Where A is area and h is height

Since their cross sections are the same, then volume depends on height.

If 12cm equals 2 liters

8cm equals x

X=(2*8)/12=1.3333333333333 liters

Approximayely, the smaller pail has capacity of 1.33 liters

7 0
2 years ago
"According to a 2018 Gallup poll, 5% of U.S. adults consider themselves to be vegetarian. Nonwhite Americans (9%) are three time
Tasya [4]

Answer:

(c) Observational Distribution

(d) Diet Choice

Step-by-step explanation:

Out of 1033 American adults interviewed in July 2018, 5% consider themselves to be vegetarian.

Since the poll observes the diet habit of the respondents, the cited 5% is part of the Observational distribution of whether the respondent is a vegetarian or not (which is the Diet Choice).

If on the other hand, the poll seeks to manipulate the conditions of the study, it would have been an experimental distribution.

3 0
1 year ago
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