How to derive the formula for the surface area of a cylinder?

Stacie is a resident at your medical facility where you work. You are asked to chart the amount of solid food that she consumes.

enot [183]

4.75 ounces of solid food

7 0

2 years ago

The championship record in baseball in a certain year was 52 games won, and 14 lost. What percent of the games were won?

slamgirl [31]

Number of games won/Number of total games played x 100%

52/66 x 100% = 78.79%

Hope u understood! :)

5 0

2 years ago

On Monday, the closing value of a share of stock in Company ABC, was 74.01. On Tuesday, it closed at 73.67, and on Wednesday, it

Elenna [48]

Answer:

$957.71$

Step-by-step explanation:

Given: On Monday, the closing value of a share of stock in Company ABC, was $74.01$ . On Tuesday, it closed at $73.67$ , and on Wednesday, it closed at $74.32$ . On Thursday, the change in stock value was $-1.48$ . And, on Friday, Company ABC's stock gained $0.89$ points.

To Find: One shareholder owns $13$ shares of Company ABC's stock. What was the total value of their stock in this company at the close of Tuesday.

Solution:

Closing value of Shares of company ABC on Monday $=74.01$

Closing value of Shares of company ABC on Tuesday $=73.67$

Closing value of Shares of company ABC on Wednesday $=74.32$

on Thursday change in stock value was $-1.48$

Closing value of Shares of company ABC on Thursday $=72.84$

on Friday comapny's stock gained $0.89$ points

Closing value of Shares of company ABC on Friday $=73.73$

As one shareholder owns $13$ shares of company

Total value of shares on Tuesday is

$=\text{number of shares}\times\text{closing stock value on tuesday}$

$=13\times73.67$

$=957.71$

Hence total value of shareholder's share on close of Tuesday is $957.71$

6 0

2 years ago

Read 2 more answers

A company logo is made up of a square and three identical triangles. What is the area of the logo? Enter your answer in the box.

garri49 [273]

Given:
square with sides measuring 7 cm.
3 triangles attached to three sides of the square. A line bisecting one triangle is measured at 4 cm.

Area of a square = s² = (7cm)² = 49 cm²

Area of a triangle = hb/2 = (4cm*7cm)/2 = 14 cm²
Area of the 3 triangles = 14 cm² x 3 = 42 cm²

Total area of the logo = 49 cm² + 42 cm² = 91 cm²

7 0

1 year ago

Read 2 more answers

A member of a student team playing an interactive marketing game received the fol- lowing computer output when studying the rela

nirvana33 [79]

Answer:

$p_v = 2*P(t_{n-2} > |t_{calc}|)= 0.91$

So on this case for the significance level assumed $\alpha=0.05$ we see that $p_v >\alpha$ so then we can conclude that the result is NOT significant. And we don't have enough evidence to reject the null hypothesis.

So on this case is not appropiate say that :"the more we spend on advertising this product, the fewer units we sell" since the slope for this case is not significant.

Step-by-step explanation:

Let's suppose that we have the following linear model:

$y= \beta_o +\beta_1 X$

Where Y is the dependent variable and X the independent variable. $\beta_0$ represent the intercept and $\beta_1$ the slope.

In order to estimate the coefficients $\beta_0 ,\beta_1$ we can use least squares procedure.

If we are interested in analyze if we have a significant relationship between the dependent and the independent variable we can use the following system of hypothesis:

Null Hypothesis: $\beta_1 = 0$

Alternative hypothesis: $\beta_1 \neq 0$

Or in other words we want to check is our slope is significant (X have an effect in the Y variable )

In order to conduct this test we are assuming the following conditions:

a) We have linear relationship between Y and X

b) We have the same probability distribution for the variable Y with the same deviation for each value of the independent variable

c) We assume that the Y values are independent and the distribution of Y is normal

The significance level assumed on this case is $\alpha=0.05$

The standard error for the slope is given by this formula:

$SE_{\beta_1}=\frac{\sqrt{\frac{\sum (y_i -\hat y_i)^2}{n-2}}}{\sqrt{\sum (X_i -\bar X)^2}}$

Th degrees of freedom for a linear regression is given by $df=n-2$ since we need to estimate the value for the slope and the intercept.

In order to test the hypothesis the statistic is given by:

$t=\frac{\hat \beta_1}{SE_{\beta_1}}$

The p value on this case would be given by:

$p_v = 2*P(t_{n-2} > |t_{calc}|)= 0.91$

So on this case for the significance level assumed $\alpha=0.05$ we see that $p_v >\alpha$ so then we can conclude that the result is NOT significant. And we don't have enough evidence to reject the null hypothesis.

So on this case is not appropiate say that :"the more we spend on advertising this product, the fewer units we sell" since the slope for this case is not significant.

3 0

2 years ago