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2 years ago

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Karlie makes $8.00 per hour. Karlie worked 16 hours in one week. Karlie wants to purchase a bike that costs $70.00. How much mon

ey will Karlie have after she purchases the bike

2 answers:

shepuryov [24]2 years ago

6 0

Answer:

58

Step-by-step explanation:

Anni [7]2 years ago

5 0

Answer:

Step-by-step explanation:

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A clothing vendor estimates that 78 out of every 100 of its online customers do not live within 50 miles of one of its physical

Korolek [52]

Answer:

78% probability that a randomly selected online customer does not live within 50 miles of a physical store.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

In this problem, we have that:

Total outcomes:

100 customers

Desired outcomes:

A clothing vendor estimates that 78 out of every 100 of its online customers do not live within 50 miles of one of its physical stores. So the number of desired outcomes is 78 customers.

Using this estimate, what is the probability that a randomly selected online customer does not live within 50 miles of a physical store?

$p = \frac{78}{100} = 0.78$

78% probability that a randomly selected online customer does not live within 50 miles of a physical store.

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2 years ago

for a school fundraiser troy sold 28 bags of popcorn and 40 candy bars and made 282. jake sold 17 bags of popcorn and 20 candy b

Nataliya [291]

Each bag of popcorn is equal to 6.5 dollars

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2 years ago

Rectangle EFGH is translated according to the rule T–5, 9(x, y). If the coordinates of the pre-image of point H are (–2, –3), wh

photoshop1234 [79]

H' = -2 -5, -3 + 9 = (-7, 6)

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2 years ago

Read 2 more answers

Diego has $500 in his savings account. each month, he takes out $20 to pay for karate class.

lyudmila [28]

Answer:

25m?

Step-by-step explanation:

I mean I'm not sure what the question is asking for but after 25 months he won't have any money left lol hope that helped ♡

7 0

1 year ago

Students in a statistics class are conducting a survey to estimate the mean number of units students at their college are enroll

GaryK [48]

Answer:

(11.76, 12.84)

Step-by-step explanation:

Given that we can assume that the distribution of individual student enrollment units at this college is approximately normal.

Sample mean =12.3

sample std dev s = 1.9 units

Sample size = 47

Std error = $\frac{1.9}{\sqrt{47} } \\=0.277$

Z critical value for 95% = 1.96

Margin of error = $1.96*0.277=0.543$

Confidence interval =

$(12.3-0.543, 12.3+0.543)\\= (11.757, 12.843)$

=(11.76, 12.84)

3 0

1 year ago