Answer:
If a box is supposed to contain 18 ounces, and the acceptable error is 1 ounce, then the acceptable range is:
18 oz - 1oz = 17oz to 18oz + 1oz = 19oz
Then the acceptable range is (17oz, 19oz)
if the weight is smaller than 17 oz, the box is not acceptable.
If the weight is bigger than 19 oz, the box is not acceptable.
Then the graph of the boxes that can not be sold as full boxes is:
<---16---------17-------18--------19-------20----------->
where 17oz and 19oz are not included, because are acceptable weigths.
Part 1 : A=1/2 ap P= 2A/a = 1000/10 = 100 ft.
Part 2 : (100 ft.)($7.95/ft) = $795
I'm not sure for part 3.
Answer:
Side of 22 and height of 11
Step-by-step explanation:
Let s be the side of the square base and h be the height of the tank. Since the tank volume is restricted to 5324 ft cubed we have the following equation:


As the thickness is already defined, we can minimize the weight by minimizing the surface area of the tank
Base area with open top 
Side area 4sh
Total surface area 
We can substitute 


To find the minimum of this function, we can take the first derivative, and set it to 0



![s = \sqrt[3]{10648} = 22](https://tex.z-dn.net/?f=s%20%3D%20%5Csqrt%5B3%5D%7B10648%7D%20%3D%2022)

Answer:
The last two terms of the expression are

Both the last terms has variable of degree equal to (2+4=6) and (3+3=6).So, the first term must have degree greater than 6.
Correct Options are

Answer:
Yes. Juan will break even because 16 and -16 are a zero pair. -16 is the additive inverse of 16. So the sum will be 0.