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Akimi4 [234]
1 year ago
11

Convert to the nearest tenth. gal. = 319 qt.

Mathematics
1 answer:
lisov135 [29]1 year ago
5 0
The answer is 79.75 converted to 80.0
Hope this helps!!
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There are 15 people in a party, including Hannah and Sarah. We divide the 15 people into 3 groups, where each group has 5 people
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Answer:15/3

Step-by-step explanation:

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Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
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If y=3x^2+30x+71, then 
y=3(x^2+10x)+71=3(x^2+2\cdot5x+25-25)+71
y=3((x+5)^2-25)+71=3(x+5)^2-75+71=3(x+5)^2-4. So, in the first gap you can write 5 and in the second you can write -4.
Since (x+5)^2\ge 0, the minimum value of y is when (x+5)^2=0. The solution of the last equation is x=-5 and then y=-4 -- these are numbers, which you can write in the third and fourth gaps.

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PLEASE HELP ASAP: A particle is moving with velocity v(t) = t2 – 9t + 18 with distance, s measured in meters, left or right of z
dimaraw [331]
1) \frac{v(8)-v(0)}{8 - 0} = \frac{10-18}{8} = -1\frac{m}{s}.
2) v(5) = 5^2-9*5+18 = 25-45+18 = -2\frac{m}{s}.
3) The particle is moving right when the velocity function is positive: 0\ \textless \ t\ \textless \ 3 or 6\ \textless \ t\ \textless \ 8.
4) When 0\ \textless \ t\ \textless \ \frac{9}{2} the particle is slowing down because the acceleration is close to zero \Rightarrow the particle is speeding up when acceleration is increasing away from zero: \frac{9}{2}\ \textless \ t\ \textless \ 8.
5) (\frac{1}{8})* \int\limits^8_0 {t^2-9t+18dt}=\frac{1}{8}*(\frac{t^3}{3}-(\frac{9}{2}*t^2+18t)_{0}^{8}= \\=(\frac{1}{8})*(\frac{8^3}{3}-(\frac{9}{2})*8^2+18*8)=\frac{8^2}{3}-(\frac{9}{2})*8+18=3\frac{1}{3} \frac{m}{s}.
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2 years ago
Which congruence theorem can be used to prove △BDA ≅ △DBC? Triangles B D A and D B C share side D B. Angles C B D and A D B are
Tomtit [17]

Answer:

A. Hypotenuse-leg (HL) congruence.

HL, when you have 2 right triangles and their hypotenuses are congruent you are able to say HL

Step-by-step explanation:

We know that the hypotenuse-leg theorem states that if the hypotenuse and one leg of a right triangle are congruent to hypotenuse and corresponding leg of another right triangle, then the triangles are congruent.  

hypotenuse(AB) of △BDA equals to hypotenuse (CD) of △DBC.  

BDA and DBC share a common side DB.

Using Pythagorean theorem we will get,

CD^{2}=DB^{2}+BC^{2}...(1)  \\\\AB^{2}=DB^{2}+AD^{2}...(2)

We have been given that CD=AB, Upon using this information we will get,

DB^{2}+BC^{2}=DB^{2}+AD^{2}

Upon subtracting DB^{2} from both sides of our equation we will get,

BC^{2}=AD^{2}\\\\BC=AD

<h3>Therefore, by HL congruence △BDA ≅ △DBC.</h3>
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Isabelle is 7 years old
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