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1 year ago

Which ordered pairs are solutions to the inequality 2y−x≤−6 ?

1 answer:

4 0

Given inequality: 2y−x ≤ −6

Option-1 : (-3,0)
2×0 - (-3) = 0 + 3 = 3 > -6
Not satisfied

Option-2 : (6,1)
2×1 - 6 = 2 - 6 = -4 > -6
Not satisfied

Option-3 : (1, -4)
2×(-4) - 1 = -8 - 1 = -9 < -6
Satisfied.
Thus, (1, -4) is a solution.

Option-4 : (0, -3)
2×(-3) - 0 = -6 - 0 = -6 = -6
Satisfied.
Thus, (0, -3) is a solution.

Option-5 : (2, -2)
2×(-2) - 2 = -4 - 2 = -6 = -6
Satisfied.
Thus, (2, -2) is a solution.

Solutions are: (1, -4), (0, -3) , (2, -2)

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in a random sample of 200 people, 154 said that they watched educational television. fine the 90% confidence interval of the tru

melisa1 [442]

Answer:

[0.7210,0.8189] = [72.10%, 81.89%]

Step-by-step explanation:

The sample size is

n = 200

the proportion is

p = 154/200 = 0.77

Since both np ≥ 10 and n(1-p) ≥ 10

We can approximate this discrete binomial distribution with the continuous Normal distribution. As the sample size is large enough, not applying the continuity correction factor makes no significant difference.

The approximation would be to a Normal curve with this parameters:

Mean

p = 0.77

Standard deviation

$\bf s=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.77*0.23}{200}}=0.0298$

The 90% confidence interval for the proportion would be then

$\bf [0.77-z^*0.0298, 0.77+z^*0.0298]$

where $\bf z^*$ is the 10% critical value for the Normal N(0,1) distribution , this is a value such that the area under the N(0,1) curve outside the interval $\bf [-z^*,z^*]$ is 10%=0.1

We can either use a table, a calculator or a spreadsheet to get this value.

In Excel or OpenOffice Calc we use the function

NORMSINV(0.95) and we get a value of 1.645

The 90% confidence interval for the proportion is then

$\bf [0.77-1.645^*0.0298, 0.77+1.645^*0.0298]=[0.7210,0.8189]$

This means there is a 90% probability that the proportion of people who watch educational television is between 72.10% and 81.89%

If the television company wanted to publicize the proportion of viewers, do you think it should use the 90% confidence interval?

Yes, I do.

5 0

1 year ago

Giselle wants to buy a condo that has a purchase price of $163,000. giselle earns $2,986 a month and wants to spend no more than

Alborosie

The condo costs $163,000, earns $2,986 per month, spends no more than 25% of her income, then if she pays $33,000 for the down payment, the remaining amount would be $130,000. Since 20% of the initial cost is only $32,600, she can adjust her down payment to 20.25% of the initial cost so that the annual payments would be less.

6 0

2 years ago

Read 2 more answers

Determine the input value for which the statement f(x) = g(x) is true. From the graph, the input value is approximately_______ .

Julli [10]

In this question , we have a graph given, and we have to find the x coordinate of the intersection point .

From the graph , the input value is approximately 3.3 .

In the graph,

$f(x) =3$

And for g(x), we need the slope and y intercept .

Slope is the ratio of rise and run .

Here rise equals 3 units and run equals 2 units. And the graph touch the y axis at -2 .

So the equation of g(x) is

$g(x) = \frac{3}{2}x -2$

We need to do

$f(x)= g(x)$

Substituting the values of the two functions, we will get

$3 = \frac{3}{2}x -2$

Adding 2 to both sides

$5 = \frac{3}{2}x$

Cross multiplication

$10 =3x
\\
x = \frac{10}{3}$

$x = 3.3$

So the input value is 3.3 approx

6 0

1 year ago

Read 2 more answers

NEED HELP ASAP!!

juin [17]

The answer is C.

Note when Soro divides both sides by -2.5 to solve the equation. When multiplying/dividing by a negative number, one should always reverse the inequality sign, but Soro forgot to do this.

-2.5x≥-30

After this step, the answer SHOULD HAVE been:

x≤12

Let me know if you need any clarifications, thanks!

8 0

1 year ago

Read 2 more answers

Decrease £16870 by 3% , give your answer rounded 2 decimal places

lidiya [134]

To decrease it by 3% we need to fine 97% of it and 97% is the same as 0.97

16870 times 0.97=16363.9

16870 decreased by 3% is 16363.9

I hope I've helped!

5 0

1 year ago