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olchik [2.2K]
2 years ago
14

Which ordered pairs are solutions to the inequality 2y−x≤−6 ?

Mathematics
1 answer:
Vinil7 [7]2 years ago
4 0
Given inequality: 2y−x ≤ −6

Option-1 : (-3,0)
2×0 - (-3) = 0 + 3 = 3 > -6
Not satisfied

Option-2 : (6,1)
2×1 - 6 = 2 - 6 = -4 > -6
Not satisfied

Option-3 : (1, -4)
2×(-4) - 1 = -8 - 1 = -9 < -6
Satisfied.
Thus, (1, -4) is a solution.

Option-4 : (0, -3)
2×(-3) - 0 = -6 - 0 = -6 = -6
Satisfied.
Thus, (0, -3) is a solution.

Option-5 : (2, -2)
2×(-2) - 2 = -4 - 2 = -6 = -6
Satisfied.
Thus, (2, -2) is a solution.

Solutions are: (1, -4), (0, -3) , (2, -2)

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Find the value of sin100.sin120.sin140.sin160​
NARA [144]

The value of sin100.sin120.sin140.sin160 is 0.1875

Step-by-step explanation:

To find the value of sin100.sin120.sin140.sin160, let us find the value of each angle.

The value of sin100=0.9848

The value of sin120=\frac{\sqrt{3} }{2}

The value of sin140=0.6428

The value of sin160=0.3420

Substituting the values of sin, we get,

sin100.sin120.sin140.sin160=0.9848*\frac{\sqrt{3} }{2} *0.6428*0.3420

Multiplying the values of sin, we get,

sin100.sin120.sin140.sin160=0.1875

Thus, the value of sin100.sin120.sin140.sin160 is 0.1875

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A hose with a larger diameter working alone can fill a swimming pool in 9 hours. A hose with a smaller diameter working alone ca
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