The value of constant of variation "k" is 
<em><u>Solution:</u></em>
Given that the direct variation is:
y = kx ----- eqn 1
Where "k" is the constant of variation
Given that the point is (5, 8)
<em><u>To find the value of "k" , substitute (x, y) = (5, 8) in eqn 1</u></em>
Thus the value of constant of variation "k" is
Answer: 13.375% per year
Explanation:
1) Depreciation is the loss of value: $ 20,000.00 - $ 14,650.00 = $ 5,350
2) The percent of depreciation is amount of the depreciation divided by the value of the car when purchased, times 100.
That is (5,350 / $ 20,000) * 100 = 26.75 %
2) The rate is percent of depreciation per year:
depreciation rate = % of depreciation / number of years = 26.75% / 2 = 13.375% per year.
For two objects with a finite constant mass, Fg is inversely proportional to the square of the distance between them. As r gets smaller the gravitational force increases. When the two objects are touching Fg is highest. But the mass of an object is focussed at its centre, the centre of mass. When the objects are touching their centres of mass are still separated. The graph has a vertical asymptote at r=0, implying an infinite gravitational force.
Answer:
The expected number of coupon is 
Step-by-step explanation:
From the question we are told that
The probability that a $10 coupons delivered by mail will be redeemed is p = 0.16
The sample size is n = 10
Generally the expected number of coupons that will be redeemed is mathematically represented as
=> 
=>
Answer:
D
Step-by-step explanation:
Under a clockwise rotation about the origin of 90°
a point (x, y ) → (y, - x ), thus
C(1, 2 ) → C'(2, - 1 ) → D
